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n200080 [17]
3 years ago
8

Simplify the expression: 4x - (x + 3) + 5(2x - 8)

Mathematics
2 answers:
kirill [66]3 years ago
4 0

Answer:

Step-by-step explanation:

4x - (x + 3) +5(2x - 8) = 4x + x*(-1) + 3*(-1) + 2x * 5 + (-8) * 5

                                  = 4x - x - 3 + 10x - 40 {combine like terms}

                                  = 4x - x + 10x - 3 - 40

                                 = 13x - 43

Natasha2012 [34]3 years ago
4 0

Answer:

13x-43

Step-by-step explanation:

have a spectacular day! <3

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Dan and Becca have cups that are the same size. Dans cup is 1/4 full of water. Beccas cup is 1/6 full of water. Compare the amou
matrenka [14]

Answer:

>

Step-by-step explanation:

1/4 is greater than 1/6.

8 0
3 years ago
1. At the school bookstore, Harrison purchases 3 notebooks for $2.50 each, 10 pens for $0.35 each, and 5 mechanical pencils for
Artemon [7]
Find cost of pens and mechanical pencils

pen cost=number of pens times cost pe pen
pencost=10 times 0.35=3.50

mech cost=number of mechs times cost pe mech
mechcost=5 times 0.89=4.45

4.45 is more than 3.50
yes, mech cost mre than pens




8 0
3 years ago
In ΔJKL, k = 3.7 cm, ∠K=15° and ∠L=41°. Find the length of j, to the nearest 10th of a centimeter.
Alexandra [31]

Answer:

The length of side j is 11.85cm

Step-by-step explanation:

Given that

In triangle JKL,

\angle k=15

\angle l=41

Side k=LJ=3.7cm

To find side j=KL:

By using sine rule,

We can write as

\frac{SinK}{LJ} = \frac{SinL}{JK} = \frac{SinJ}{KL} \\\frac{Sin15}{3.7} = \frac{Sin41}{JK} = \frac{SinJ}{KL}

Using property of triangle,

\angle k+\angle l+\angle j=180

15+41+\angle j=180

\angle j=124

\frac{Sin15}{3.7} = \frac{Sin41}{JK} = \frac{Sin124}{KL}\\\frac{Sin15}{3.7} = \frac{Sin124}{KL}\\KL=3.7\frac{Sin124}{Sin15}\\KL=3.7\frac{0.8290}{0.2588}\\KL=11.85cm

Thus,

The length of side j is 11.85cm

8 0
3 years ago
Which expression is equivalent tos cos(3x)sinx
posledela
Where are the following expressions
3 0
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Is the function given by, (Picture Provided)
Sever21 [200]

Answer:

a. yes

Step-by-step explanation:

The given function is

f(x)=\left \{ {{3x-2,if\:x\le3} \atop {10-x,if\:x\:>\:3}} \right.

f(3)=\left \{ {{3(3)-2,if\:x\le3} \atop {10-3,if\:x\:>\:3}} \right.=7

\lim_{x \to 3^-} f(x)=3(3)-2=7

\lim_{x \to 3^+} f(x)=10-3=7

\Rightarrow \lim_{x \to 3} f(x)=7

Since;

\lim_{x \to 3} f(x)=f(3)

The function is continuous at x=3

7 0
3 years ago
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