Question

The sum of three different two-digit prime numbers is 79. the largest of the numbers is 43. the difference of the other two is 10. what is the product of the three numbers

Answer 1

Let the number be x,y and 43
y-x=10
thus
y=10+x
the sum off the numbers will be:
x+y+43=79
plugging the values we get:
x+(10+x)+43=79
solving for x we get:
2x+53=79
2x=79-53
2x=26
x=26/2=13
hence:
y=10+13=23
thus the numbers are 13,23 and 43
the product of the number will be:
13×23×43
=12,857

Answer: 12,857