Ask question

Ask question

All categories

3 years ago

13

Dan and Becca have cups that are the same size. Dans cup is 1/4 full of water. Beccas cup is 1/6 full of water. Compare the amou

nt of water in each cup using <,>, or =.
I-Ready™

1 answer:

matrenka [14]3 years ago

8 0

Answer:

>

Step-by-step explanation:

1/4 is greater than 1/6.

You might be interested in

If x= 1/2-√3 , prove that x³-2x²-7x+5=3

prohojiy [21]

$x=\frac{1}{2}-\sqrt3\\\\x^3-2x^2-7x+5=3\\\\(\frac{1}{2}-\sqrt3)^3-2(\frac{1}{2}-\sqrt3)^2-7(\frac{1}{2}-\sqrt3)+5\\\\=(\frac{1}{2})^3-3\cdot(\frac{1}{2})^2\cdto\sqrt3+3\cdot\frac{1}{2}\cdot(\sqrt3)^2-(\sqrt3)^3-...\\\\...-2[(\frac{1}{2})^2-2\cdot\frac{1}{2}\cdot\sqrt3+(\sqrt3)^2]-\frac{7}{2}+7\sqrt3+5$

$=\frac{1}{8}-\frac{3\sqrt3}{4}+\frac{9}{2}-3\sqrt3-2(\frac{1}{4}-\sqrt3+3)-\frac{7}{2}+7\sqrt3+5\\\\=\frac{1}{8}+\frac{9}{2}-\frac{1}{2}-6-\frac{7}{2}+5-\frac{3}{4}\sqrt3-3\sqrt3+2\sqrt3+7\sqrt3\\\\=\frac{1}{8}+\frac{1}{2}-1+5\frac{1}{4}\sqrt3=\frac{1}{8}-\frac{1}{2}+5\frac{1}{4}\sqrt3=\frac{1}{8}-\frac{4}{8}+5\frac{1}{4}\sqrt3\\\\=-\frac{3}{8}+5\frac{1}{4}\sqrt3\neq3$

6 0

3 years ago

Suppose A = {1, 7, 13, 17, 21, 25} and B = {7, ,14, 21, 28, 35, 42}. What is A∩B?

Lubov Fominskaja [6]

$A\cap B=\{7,21\}$

8 0

4 years ago

Convert the following <br><br>250cm to m

dmitriy555 [2]

100 cm = 1m

1 cm = 1/100

250 cm = 1/100*250

= 2.5m

This is Right answer...

4 0

3 years ago

If EFH = (5x + 1)°, HFG = 62°, and EFG = (18x + 11)°, find EFH

olga55 [171]

Given:

Consider the below figure attached with this question.

∠EFH = (5x + 1)°, ∠HFG = 62°, and ∠EFG = (18x + 11)°

To find:

The measure of ∠EFH.

Solution:

From the figure it is clear that ∠EFG is divide in two parts ∠EFH and ∠HFG. So,

$\angle EFG=\angle EFH+\angle HFG$

$18x+11=(5x+1)+(62)$

$18x+11=5x+63$

Isolate variable terms.

$18x-5x=63-11$

$13x=52$

Divide both sides by 13.

$x=\dfrac{52}{13}$

$x=4$

The value of x is 4.

$\angle EFH=(5x+1)^\circ$

$\angle EFH=(5(4)+1)^\circ$

$\angle EFH=(20+1)^\circ$

$\angle EFH=21^\circ$

Therefore, the measure of ∠EFH is 21°.

8 0

3 years ago

-5 < x - 4 greater than it equal 1

saul85 [17]

We have expression $-5 < x - 4 \geq 1$ that renders the system of inequalities,

$\begin{cases}-5 < x - 4 \\x - 4 \geq 1\end{cases}$

Which can be simplified to,

$\begin{cases}x > -1 \\x \geq 5\end{cases}$

So what we get is something greater than -1 and at the same time greater or equal to 5, so the solution is,

$x\in(\infty,-1)\cap(\infty, 5]=\boxed{(\infty,5]}$ .

Hope this helps.

6 0

3 years ago