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Yuki888 [10]
3 years ago
15

Type the missing number that makes these fractions equal: 2/8=1/?

Mathematics
2 answers:
s2008m [1.1K]3 years ago
5 0
The answer is 1/4...........
Hoochie [10]3 years ago
5 0

Answer:

2/8 is equivalent to 1/4

So

The answer is 1/4

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What is 4pie=w-6 pie
Marina CMI [18]
W= 31.4
Step 1: 4*Pi = 12.566370614359 
Step 2: -6*Pi = -18.849555921539 

Step 3: Rewrite equation (12.566370614359=w-18.849555921539) 
Step 4: Move the number that is equivalent to 6Pi over to the other side of the equal sign to get the variable alone.  (12.566370614359+18.849555921539 = 31.415926535898 ) The problem should now look like this, <span>31.415926535898=w

Step 5: Divide the numbers (which you don't really need to do here since the "number" in front of w is 1. This is helpful to know for future problems though.)

Step 6: Round to the nearest tenths place (or however you need to) giving you the final answer of 31.4 </span>
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Alex started reading her book for 2 hours and 35 minutes one day and finished by reading 1 hour 52 minutes the next day. how lon
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4 hours and 27 minutes.
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A mothers age 41 has two children ages seven and 12 how old will the children be when you combine ages are equal to the mothers
Vesnalui [34]
Th answer is 23+19= 41
7 0
4 years ago
Do you guys now the answer I need it ASAP please
HACTEHA [7]

Answer:I think that it would be either b or c

Step-by-step explanation:

4 0
3 years ago
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Phonesmart is having a sale on Bananas. If you buy one Banana at full price, you get a second at half price. When couples come i
Mice21 [21]

Answer:

<u>The probability that a couple buys a pair of Bananas is 1/3 or 33.3%</u>

Step-by-step explanation:

Let's recall that the formula of probability is:

Probability = Number of favorable outcomes/Total number of possible outcomes

What is the probability that a couple buys a pair of Bananas?

For answering this question, we first need to calculate the probability of buying a first Banana, given that when couples come in to buy a pair of phones, sales of Apricots and Bananas are equally likely:

Probability of buying a first Banana = 1/2

Probability of buying a first Apricot = 1/2

Now, we can calculate the probability of buying a second Banana, given that the second phone is twice as likely to be a Banana rather than an Apricot.

Probability of buying a second phone = 1

Probability of buying a second Apricot = x

Probability of buying a second Banana = 2x

Solving for x, we have:

x + 2x = 1

3x = 1

x = 1/3 ⇒ 2x = 2/3

Thus, probability of buying a second Banana = 2/3

Finally,

Probability that a couple buys a pair of Bananas = Probability of buying a first Banana * Probability of buying a second Banana

Replacing with the values we know:

Probability that a couple buys a pair of Bananas = 1/2 * 2/3 = 2/6 = 1/3

1/3 = 33.3%

<u>Probability that a couple buys a pair of Bananas = 1/3 or 33.3%</u>

6 0
3 years ago
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