A^2 + b^2 =c^2 ; c = hypotenuse, a and b: legs
4^2 + 5^2 = c^2
16 + 25 = c^2
41 =c^2
so c = <span>sqrt(41) = 6.40312424
</span>hypotenuse = 6.40312424
Because if you divide4÷23 you cant if were 24. you can
If I’m correct it should be 6+4i good luck
Answer:
-4<f
Step-by-step explanation:
i am pretty sure this is correct, haven´t done it since freshman year haha.
Answer:
The answer to your question is 3, 9, 19, 33, 51
Step-by-step explanation:
Sequence an = 2n² + 1
1st term a₁ = 2(1)² + 1 = 2(1) + 1 = 2 + 1 = 3
2nd term a₂ = 2(2)² + 1 = 2(2)² + 1 = 2(4) + 1 = 8 + 1 = 9
3rd term a₃ = 2(3)² + 1 = 2(3)² + 1 = 2(9) + 1 = 18 + 1 = 19
4rd term a₄ = 2(4)² + 1 = 2(4)² + 1 = 2(16) + 1 = 32 + 1 = 33
5th term a₅ = 2(5)² + 1 = 2(5)² + 1 = 2(25) + 1 = 50 + 1 = 51