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3 years ago

Which equation is equivalent to (1/3)^x=27^x+2?

Mathematics

1 answer:

ruslelena [56]3 years ago

6 0

Ok so the answer is D because first I solved the equation because you can’t find which answer choice it is equivalent to if you didn’t solve it ... so I solved the equation and got x=-3/2 how I solved this is

3^-x = 3^3x+6 ... since the bases are the same, set the exponents equal
-x=3x+6..... move the variable to the left-hand side and change its side
-x-3x=6 ... collect like terms
-4x = 6..... divide both sides of the equation by -4 and I got x=-3/2
I don’t want this text to be that long so they both seem calculated the same way that’s why i got -3/2 hope that helps;-;

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3 years ago

How can I solve 4x-2>3x+5

cluponka [151]

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3 years ago

Evaluate - 4/8 ./. 8 2/3

LenaWriter [7]

Answer:

The answer is 13/3.

Step-by-step explanation:

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2 years ago

Please help me complete this !! 12points

Svet_ta [14]

Answer:

x1=1

x2=3

y1=5

y2=1

midpoint= (x1+x2/2, y1+y2/2)=(1+3/2,5+1/2)=(2,3)

x1=2

x2=4

y1=4

y2=6

midpoint= (x1+x2/2, y1+y2/2)=(2+4/2,4+6/2)=(3,5)

x1= -2

x2=4

y1=4

y2= -6

midpoint= (x1+x2/2, y1+y2/2)=(-2+4/2,4-6/2)=(1,-1)

x1=0

x2=0

y1=3

y2=5

midpoint= (x1+x2/2, y1+y2/2)=(0/2,3+5/2)=(0,4)

x1= -2

x2=2

y1= -6

y2=6

midpoint= (x1+x2/2, y1+y2/2)=(-2+2/2,-6+6/2)=(0,0)

x1=1

x2=4

y1=4

y2=5

midpoint= (x1+x2/2, y1+y2/2)=(1+4/2,4+5/2)=(5/2,9/2)

x1=-3

x2=-4

y1=5

y2=5

midpoint= (x1+x2/2, y1+y2/2)=(-3-4/2,5+5/2)=(-7/2,5)

x1=5

x2= -4

y1=2

y2=6

midpoint= (x1+x2/2, y1+y2/2)=(5-4/2,2+6/2)=(1/2,4)

3 0

2 years ago

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Answer:

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2 years ago