1/5(x-2)=1/10(x+6) and <br> 0.35(x+4)=0.25(x-6) please

Use the game spinner for questions 1-4. In your final answer, include all necessary calculations.

IrinaVladis [17]

Answer:

P (Even number) = 1/2

P(spinner will land on an odd number) = 1/2

P(spinner will not land on 2 or 3) = 3/4

P(spinner will not land on a multiple of 3) = 3/4

Step-by-step explanation:

Here, while spinning the spinner total possible outcomes

are 8 = {1,2,3,4,5,6,7,8}

Now, $\textrm{P(E)} = \frac{\textrm{Number of favorable outcomes }}{\textrm{Total numberof outcomes}}$

a) E: Probability of getting even number

Favorable outcomes are {2,4,6,8}

Hence, $P(E) = \frac{4}{8} = \frac{1}{2}$

b)E: Probability that the spinner will land on an odd number.

Favorable outcomes are {1,3,5,7}

Hence, $P(E) = \frac{4}{8} = \frac{1}{2}$

c) E: Probability that the spinner will not land on 2 or 3

Favorable outcomes are {1, 4,5,6,7,8}

Hence, $P(E) = \frac{6}{8} = \frac{3}{4}$

d) E: Probability that the spinner will not land on a multiple of 3

Favorable outcomes are {1,2,4,5,7,8}

Hence, $P(E) = \frac{6}{8} = \frac{3}{4}$

3 0

2 years ago

I need help with this stupid question, my teacher got me confused when he kept talking about different things!

Art [367]

Answer:

2 5/8

Step-by-step explanation:

1 3/4 + 7/8

add the fractions together

look for the lcm bwt 4 and 8

1 6 + 7

____

8

= 13/8 = 1 5/8

1 + 1 5/8

= 2 5/8

6 0

2 years ago

Which expression is equivalent to the expression below? StartFraction 6 c squared 3 c Over negative 4 c 2 EndFraction divided by

Fudgin [204]

The given equation $(6c^2+3c)/(-4c+2)\div (2c+1)/(4c-2)$ is equivalent to the expression -3c.

Given that, the expression can be written as.

$(6c^2+3c)/(-4c+2)\div (2c+1)/(4c-2)$

By simplifying the above equation,

$\dfrac{6c^2+3c}{-4c+2}\div \dfrac{2c+1}{4c-2}$

By taking out the common terms from the equation,

$\dfrac{3c(2c+1)}{2(-2c+1)}\div\dfrac{2c+1}{2(2c-1)}$

By simplifying the above equation by cancel out the common factors.

$\dfrac{3c}{-2c+1} \div \dfrac{1}{2c-1}$

Now, by taking (-1) common from (-2c+1) we get,

$\dfrac{3c}{-1(2c-1)} \div \dfrac{1}{2c-1}$

By simplifying the above equation, we get the expression,

$-3c$

So the given equation $(6c^2+3c)/(-4c+2)\div (2c+1)/(4c-2)$ is equivalent to the expression -3c.

For more details, follow the link given below.

brainly.com/question/1301963.

7 0

2 years ago

Solve for z<br> -p(d+z) = -2z+59−p(d+z)=−2z+59

alexira [117]

$-p(d+z)=-2z+59\qquad\text{use distributive property}\\\\-pd-pz=-2z+59\qquad\text{add pd to both sides}\\\\-pz=-2z+pd+59\qquad\text{add 2z to both sides}\\\\2z-pz=pd+59\\\\z(2-p)=pd+59\qquad\text{divide both sides by}\ (2-p)\neq0\\\\\boxed{z=\dfrac{pd+59}{2-p}}$

6 0

2 years ago

(PLEASE ANSWER!!) a college student completed some courses worth 4 credits and some courses worth 3 credits. the student earned

Ierofanga [76]

The college student took 13 courses of 3 credit hours.

Step-by-step explanation:

Given,

Total credits = 59

Total courses = 18

Let,

Number of 3 credit hour courses = x

Number of 4 credit hour courses = y

According to given statement;

x+y=18 Eqn 1

3x+4y=59 Eqn 2

We will eliminate y to find the number of 3 credit hour courses, therefore,

Multiplying Eqn 1 by 4

$4(x+y=18)\\4x+4y=72\ \ \ Eqn\ 3$

Subtracting Eqn 2 from Eqn 3

$(4x+4y)-(3x+4y)=72-59\\4x+4y-3x-4y=13\\x=13$

The college student took 13 courses of 3 credit hours.

Keywords: linear equation, subtraction

Learn more about linear equations at:

#LearnwithBrainly

5 0

3 years ago

1/5(x-2)=1/10(x+6) and 0.35(x+4)=0.25(x-6) please