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OverLord2011 [107]

2 years ago

11

The temperature for 5 days is shown in the table. If on the 6th day the temperature is 83, by how much will this increase the ov

erall mean temperature?
A) 1
B) 2
C)3
D)4
Also one is eliminated it wasn’t right

1 answer:

laila [671]2 years ago

4 0

Answer:

I cant see the table

Step-by-step explanation:

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What is the value of c?<br><br> Enter your answer in the box.

Leya [2.2K]

C^2 = 10^2 + 24^2
c^2 = 100 + 576
c^2 = 676
c = 26

8 0

3 years ago

Solve the following system of equations and show all work. <br> y = x^2 + 3<br> y = x + 5

RUDIKE [14]

Since both of the equations are equal to y...set them equal to each other.. So it will then be

x^2+3=x+5
-3 -3
x^2=x+2 ---> x^2-x-2
(x-2) (x+1)
x=2,-1

7 0

3 years ago

A map of a rectangular park has a length of 4 inches and a width of 6 inches. It uses a scale of 1 inch for every 30 Miles. What

MakcuM [25]

Answer:

The actual area 21600 miles²

Step-by-step explanation:

* <em>Lets explain how to solve the problem</em>

- A drawing that shows a real object with accurate sizes reduced or

enlarged by a certain amount called the scale

- Drawing scale is a ratio between the drawing length and the

actual length

- To find the actual dimensions from the drawing dimensions use the

scale drawing

*<em> Lets solve the problem</em>

- A map of a rectangular park has a length of 4 inches and a width

of 6 inches

∴ The drawing dimensions are:

# length = 4 inches

# width = 6 inches

- The scale of the map is 1 inch foe every 30 miles

∴ The scale drawing is 1 : 30

- To find the actual area find the actual dimensions

∵ The scale drawing is 1 : 30

∵ The length = 4 inches and the width = 6 inches

- By using cross multiplication

∴ 1 : 30

4 : actual length

6 : actual width

∴ Actual length = (4 × 30)/1 = 120

∴ Actual length = 120 miles

∴ Actual width = (6 × 30)/1 = 180

∴ Actual Width = 180 miles

∴ The actual dimensions are 120 miles and 180 miles

∵ The area of any rectangle = length × width

∴ The actual area = 120 × 180 = 21600

∴ The actual area 21600 miles²

5 0

3 years ago

The area of a gymnasium is (27x + 18) square units. Factor 27x + 18 to find possible dimensions of the gymnasium.

Veronika [31]

Answer:

Dimension of gymnasium= 9 units and (3x+2) units.

Step-by-step explanation:

We have been given the area of a gymnasium is $27x+18$ square units. We are asked to find possible dimensions of gymnasium by factoring our given expression for area of gymnasium.

Let us factor our greatest common factor of our given expression. We can see that 9 is the GCF of our given expression.

$(9\times 3x+9\times 2)$

Upon factoring out 9 from our given expression we will get,

$9(3x+2)$

Therefore, the possible dimensions of the gymnasium will be 9 units and (3x+2) units as we will get the same area for gymnasium by multiplying these both dimensions.

8 0

3 years ago

Read 2 more answers

What can you say about the y-values of the two functions f(x)=3^(x)-3 g(x)=7x^2-3

Mice21 [21]

Answer: g(x) has the smallest possible y-value of -3

<u>Step-by-step explanation:</u>

f(x) = 3ˣ - 3 <em>This is an exponential graph shifted down three units. So, it has an asymptote at y = -3, which means it approaches -3 but does not touch it.</em>

Range: y > 3 (-3, ∞)

g(x) = 7x² - 3

⇒ g(x) = 7(x - 0)² - 3 <em>This is a parabola with vertex at (0, -3) </em>

Range: y ≥ 3 [-3, ∞)

5 0

3 years ago

Read 2 more answers