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3 years ago

We have 2.8 meters of rope. how many centimeters is that ?

Mathematics

1 answer:

Naily [24]3 years ago

8 0

Centi- means "hundred". There are 100 centimeters in 1 meter.
2.8m•100cm=280cm

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Jerry's strips of dry meat joint sells of these two types of dry meat. he sells twice as many bags of dried beef as he does bags

igomit [66]

Assume Jerry sells x bags of dried turkey, and 2x bags of dried beef. He profits ($2)x on dried turkey, and ($1.5)(2x) on the dried beef. Therefore, his total profit is 2x + 3x = 5x. Since this is equivalent to $500, we can solve
5x = 500
x = 100
Therefore, Jerry must sell 100 bags of dried turkey and 200 bags of dried beef.

3 0

3 years ago

Pls help I'm sleep deprived rn and am almost done with this

Mkey [24]

Answer:

6π units

Step-by-step explanation:

Given::

Radius = 4

Angle measure of partial circle (θ) = 360° - right angle = 360° - 90° = 270°

Arc length = θ/360 × 2πr

Plug in the values

= 270/360 × 2 × π × 4

= 0.75 × 8 × π

= 6π units

8 0

3 years ago

What is the slope of the line passing through the points (7, 10) and (5, 16) ?<br> Thank you

butalik [34]

Answer:

m=-3

Step-by-step explanation:

m=y2-y1/x2-x1

m=16-10/5-7

m=6/-2

m=-3

4 0

2 years ago

A track star runs two races on a certain day. The probability thathe wins the first race is 0.7, the probability that he wins th

NARA [144]

Answer:

a) 80% probability that he wins at least one race.

b) 30% probability that he wins exactly one race.

c) 20% probability that he wins neither race.

Step-by-step explanation:

We solve this problem building the Venn's diagram of these probabilities.

I am going to say that:

A is the probability that he wins the first race.

B is the probability that he wins the second race.

C is the probability that he does not win any of these races.

We have that:

$A = a + (A \cap B)$

In which a is the probability that he wins the first race but not the second and $A \cap B$ is the probability that he wins both these races.

By the same logic, we have that:

$B = b + (A \cap B)$

The probability that he wins both races is 0.5.

This means that $A \cap B = 0.5$

The probability that he wins the second race is 0.6

This means that $B = 0.6$

$B = b + (A \cap B)$

$0.6 = b + 0.5$

$b = 0.1$

The probability that he wins the first race is 0.7.

This means that $A = 0.6$

$A = a + (A \cap B)$

$0.7 = a + 0.5$

$a = 0.2$

A) he wins at least one race.

This is

$P = a + b + (A \cap B) = 0.2 + 0.1 + 0.5 = 0.8$

There is an 80% probability that he wins at least one race.

B) he wins exactly one race.

This is

$P = a + b = 0.2 + 0.1 = 0.3$

There is a 30% probability that he wins exactly one race.

C) he wins neither race

Either he wins at least one race, or he wins neither. The sum of these probabilities is 100%.

From a), we have that there is an 80% probability that he wins at least one race.

So there is a 100-80 = 20% probability that he wins neither race.

6 0

3 years ago

harriet is 2 years less than a thirnd of her brothers ace. Harriet is 3 years ols. How old is her brother? please help right no

enyata [817]

Answer:

her brother is 15 years old

Step-by-step explanation:

let 'b' = her brother's age

Harriet is 3 years old but Harriet is also '1/3b - 2'

3 = 1/3b - 2

5 = 1/3b

b = 5(3) or 15

5 0

3 years ago