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sergiy2304 [10]
3 years ago
6

Help is this correct !!!??

Mathematics
1 answer:
d1i1m1o1n [39]3 years ago
6 0

Answer:

Yes

Step-by-step explanation:

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(02.06 MC) Figure ABCD is a rhombus, and m∠BAE = 9x + 2 and m∠BAD = 130°. Solve for x. Rhombus ABCD with diagonals AC and BD and
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An angle bisector divides an angle into equal parts.

<em>The value of x is 7</em>

The given parameters are:

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Line AE is the angle bisector of \angle BAD

This means that:

\angle BAD = 2 \times \angle BAE

So, we have:

130 = 2 \times (9x + 2)

Divide both sides by 2

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Rewrite as:

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Hence, the value of x is 7

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An English teacher needs to pick 1111 books to put on his reading list for the next school year. He has narrowed down his choice
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Answer:

There are 3,659,040 ways he can choose the books to put on the list.

Step-by-step explanation:

There are

12 novels

8 plays

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The order in which the novels, plays and nonfictions are chosen is not important. So we use the combinations formula to solve this problem.

C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

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5 from a set of 12. So

C_{12,5} = \frac{12!}{5!7!} = 792

Plays:

4 from a set of 8. So

C_{8,4} = \frac{8!}{4!4!} = 70

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2 from a set of 12

C_{12,2} = \frac{12!}{2!10!} = 66

Total:

Multiplication of novels, plays and nonfiction.

T = 792*70*66 = 3,659,040

There are 3,659,040 ways he can choose the books to put on the list.

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Answer:

about 7.6 days long

Step-by-step explanation:

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