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olga_2 [115]
3 years ago
7

HELP ASAP

Mathematics
2 answers:
Sliva [168]3 years ago
8 0

Answer:770000

Step-by-step explanation:

That how much they made

babunello [35]3 years ago
8 0

Answer:

€8988.75

Step-by-step My bad that's not the answer

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ALEXIS SPENT 3 hours and 15 minutes away from home and 2 hours and 45 min is part B
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NO LINKS!!
victus00 [196]

Step-by-step explanation:

<u>Given function:</u>

  • y = |x + 4| - 1

<em>See the graph below</em>

According to the graph we see that

The minimum is (-4, -1) and zero's are (-5, 0) and (-3, 0)

<u>Function is positive: </u>

  • When x < - 5 and x > -3

<u>Negative:</u>

  • When x is between -5 and -3

<u>Increasing:</u>

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<u>Decreasing:​</u>

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3 years ago
Which of the following r-value represents the strongest correlation ?
Elena-2011 [213]
Since 0.68 is closest to 1, so the answer is 

<span>A) 0.68</span>
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3 years ago
Power Series Differential equation
KatRina [158]
The next step is to solve the recurrence, but let's back up a bit. You should have found that the ODE in terms of the power series expansion for y

\displaystyle\sum_{n\ge2}\bigg((n-3)(n-2)a_n+(n+3)(n+2)a_{n+3}\bigg)x^{n+1}+2a_2+(6a_0-6a_3)x+(6a_1-12a_4)x^2=0

which indeed gives the recurrence you found,

a_{n+3}=-\dfrac{n-3}{n+3}a_n

but in order to get anywhere with this, you need at least three initial conditions. The constant term tells you that a_2=0, and substituting this into the recurrence, you find that a_2=a_5=a_8=\cdots=a_{3k-1}=0 for all k\ge1.

Next, the linear term tells you that 6a_0+6a_3=0, or a_3=a_0.

Now, if a_0 is the first term in the sequence, then by the recurrence you have

a_3=a_0
a_6=-\dfrac{3-3}{3+3}a_3=0
a_9=-\dfrac{6-3}{6+3}a_6=0

and so on, such that a_{3k}=0 for all k\ge2.

Finally, the quadratic term gives 6a_1-12a_4=0, or a_4=\dfrac12a_1. Then by the recurrence,

a_4=\dfrac12a_1
a_7=-\dfrac{4-3}{4+3}a_4=\dfrac{(-1)^1}2\dfrac17a_1
a_{10}=-\dfrac{7-3}{7+3}a_7=\dfrac{(-1)^2}2\dfrac4{10\times7}a_1
a_{13}=-\dfrac{10-3}{10+3}a_{10}=\dfrac{(-1)^3}2\dfrac{7\times4}{13\times10\times7}a_1

and so on, such that

a_{3k-2}=\dfrac{a_1}2\displaystyle\prod_{i=1}^{k-2}(-1)^{2i-1}\frac{3i-2}{3i+4}

for all k\ge2.

Now, the solution was proposed to be

y=\displaystyle\sum_{n\ge0}a_nx^n

so the general solution would be

y=a_0+a_1x+a_2x^2+a_3x^3+a_4x^4+a_5x^5+a_6x^6+\cdots
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y=a_0(1+x^3)+a_1\displaystyle\left(x+\sum_{n=2}^\infty\left(\prod_{i=1}^{n-2}(-1)^{2i-1}\frac{3i-2}{3i+4}\right)x^{3n-2}\right)
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3 years ago
Angle A and angle B are complementary angles. If m&lt;A = x, which expression represents the number of degrees in angle B?
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Complimentary just means that they add to be 90, so you take 90 degrees and subtract the angle you already have in order to get the complementary angle
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