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Grace [21]
3 years ago
8

What are the steps to answer 28=8b+13b-35

Mathematics
1 answer:
oksian1 [2.3K]3 years ago
6 0

Let's solve this problem step by step.

28=8b+13b-35

Step 1: Bring 35 to 28.

28=8b+13b-35

+35            +35

63=8b+13b

Step 2: Add 8b and 13b.

63=21b

Step 3: Divide both sides by 21.

63/21=21b/21

So, the answer for this problem is 3=b.

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Write a sequence of transformation that maps quadrilateral ABCD onto quadrilateral A. B. C. D IN THE PICTURE
Mice21 [21]

Answer:

The sequence of transformation is reflected across the y-axis and translated 2 units down

Step-by-step explanation:

Lets revise some transformation

- If point (x , y) reflected across the x-axis

∴ Its image is (x , -y)

- If point (x , y) reflected across the y-axis

∴ Its image is (-x , y)

- If point (x , y) translate h units to the right

∴ Its image is (x + h , y)

- If point (x , y) translate h units to the left

∴ Its image is (x - h , y)

- If point (x , y) translate k units up

∴ Its image is (x , y + k)

- If point (x , y) translate k units down

∴ Its image is (x , y - k)

* Now lets solve the problem

∵ The vertices of figure ABCD are:

  A (-1 , 3) , B (1 , 0) , C (2 , 3) , D (1 , 4)

∵ The vertices of figure A"B"C"D" are:

  A" (1 , 1) , B" (-1 , -2) , C" (-2 , 1) , D" (-1 , 2)

* Lets compare between ABCD and A"B"C"D"

∵ All x-coordinates has opposite signs

  -1 ⇒ 1 , 1 ⇒ -1 , 2 ⇒ -2 , 1 ⇒ -1

∴ The ABCD is reflected across the y-axis

∵ All y-coordinates subtracted by 2

 3 ⇒ 1 , 0 ⇒ -2 , 3 ⇒ 1 , 4 ⇒ 2

∴ The ABCD is translated 2 units down

* The sequence of transformation is reflected across the y-axis

  and translated 2 units down

5 0
3 years ago
Given the function s(x) = 7x - 17, find s(-8).
Scrat [10]

Answer:

-73

Step-by-step explanation:

substitue the -8 in for x. then multiply -8 by 7 you get -56. then subtract 17.

8 0
3 years ago
Antonio owes $15 less than Maria owes. This means that Antonio's balance is _________ than Maria's balance. (Maria owes more tha
Margarita [4]
Greater is the answer for the blank space
6 0
3 years ago
Read 2 more answers
After traveling exactly half of its journey from station A to station B, a train was held up for 10 minutes. In order to arrive
Alex17521 [72]
Let's define variables:
 s = original speed
 s + 12 = faster speed
 The time for the half of the route is:
 60 / s
 The time for the second half of the route is:
 60 / (s + 12)
 The equation for the time of the trip is:
 60 / s + 60 / (s + 12) + 1/6 = 120 / s
 Where,
 1/6: held up for 10 minutes (in hours).
 Rewriting the equation we have:
 6s (60) + s (s + 12) = 60 * 6 (s + 12)
 360s + s ^ 2 + 12s = 360s + 4320
 s ^ 2 + 12s = 4320
 s ^ 2 + 12s - 4320 = 0
 We factor the equation:
 (s + 72) (s-60) = 0
 We take the positive root so that the problem makes physical sense.
 s = 60 Km / h
 Answer:
 
The original speed of the train before it was held up is:
 
s = 60 Km / h
8 0
3 years ago
If it takes B hours to walk a certain distance at the rate of 3 miles per hour, the number of hours it takes to return the same
natita [175]

Answer:

It will take 0.75B hours for the return leg

Step-by-step explanation:

Here, given that the first leg of the trip was for B hours at 3 miles per hour , we want to calculate the number of hours the return leg will take at 4 miles per hour given that it is the same distance.

Mathematically, we know that ;

Distance = speed * time

So the distance taken on the first leg of the trip would be;

Distance = 3 miles per hour * B hours = 3B miles

Now, this distance was traveled on the return leg also.

This means that the time taken here will be;

Time on return leg = distance/speed = 3B/4 = 0.75B hours

5 0
2 years ago
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