B. Knowing that it is going to rain tomorrow, and doing your homework
![\bf 2sec^2(\theta )-tan(\theta )-3=0 \\\\\\ 2[1+tan^2(\theta )]-tan(\theta )-3=0\implies 2+2tan^2(\theta )-tan(\theta )-3=0 \\\\\\ 2tan^2(\theta )-tan(\theta )-1=0\implies [2tan(\theta )+1][tan(\theta )-1]=0\\\\ -------------------------------\\\\](https://tex.z-dn.net/?f=%5Cbf%202sec%5E2%28%5Ctheta%20%29-tan%28%5Ctheta%20%29-3%3D0%0A%5C%5C%5C%5C%5C%5C%0A2%5B1%2Btan%5E2%28%5Ctheta%20%29%5D-tan%28%5Ctheta%20%29-3%3D0%5Cimplies%202%2B2tan%5E2%28%5Ctheta%20%29-tan%28%5Ctheta%20%29-3%3D0%0A%5C%5C%5C%5C%5C%5C%0A2tan%5E2%28%5Ctheta%20%29-tan%28%5Ctheta%20%29-1%3D0%5Cimplies%20%5B2tan%28%5Ctheta%20%29%2B1%5D%5Btan%28%5Ctheta%20%29-1%5D%3D0%5C%5C%5C%5C%0A-------------------------------%5C%5C%5C%5C)


bear in mind that tangent is sine/cosine or y/x
for the tangent to be negative, the signs of "y" and "x" must differ, and that happens only on the II and IV quadrants
and for the tangent to be positive, the signs must be same, and that's only on I and III quadrants.
Answer:
12 passengers can travel in Rs. 900.
Step-by-step explanation:
see the above attachment.
if you face any problem comment me, I am there for help.
hope this helps you.
Divide 6 by -8 to get the variable alone!
6/-8 < division< equation