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ddd [48]
3 years ago
9

(Middle school math) please help, thank you

Mathematics
2 answers:
Korvikt [17]3 years ago
6 0
I’m pretty sure it’s 18.6 if i did my math right
KatRina [158]3 years ago
5 0

Answer:

18.68 inches

Step-by-step explanation:

slant height² = r² + h²

slant height = \sqrt{r^{2} + h^{2}  }

sh = \sqrt{5^{2} + 18^{2} }

sh = \sqrt{25 + 324}

sh = \sqrt{349}

sh = 18.68154 inches

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Answer:

$80

Step-by-step explanation:

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3 0
3 years ago
Find the vertex of the following equation. y= -x^2+4x+3
Strike441 [17]

Answer:

D. (2,7)

Step-by-step explanation:

Hope this helps!

3 0
4 years ago
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A spherical hot-air balloon has a diameter of 55 feet. When the balloon is inflated, the radius increases at a rate of 1.5 feet
abruzzese [7]

Answer:

The time it would take to inflate the balloon to approximately two-thirds of its maximum volume is approximately 46.90 minutes

Step-by-step explanation:

The given parameters are;

The diameter of  the balloon  = 55 feet

The rate of increase of the radius of the balloon when inflated = 1.5 feet per minute

We have;

dr/dt = 1.5 feet per minute = 1.5 ft/min

V = 4/3·π·r³

The maximum volume of the balloon = 4/3 × 3.14 × 55³ = 696556.67 ft³

When the volume is two-thirds the maximum volume, we have;

2/3 × 696556.67 ft³ = 464371.11 ft³

The value of the radius, r₂ at that point is found as follows;

4/3·π·r₂³ = 464371.11 ft³

r₂³ = 464371.11 ft³ × 3/4 = 348278.33 ft³

348278.333333

r₂ = ∛(348278.33 ft³) ≈ 70.36 ft

The time for the radius to increase to the above length = Length/(Rate of increase of length of the radius)

The time for the radius to increase to the above length ≈ 70.369 ft/(1.5 ft/min) ≈ 46.90 minutes

The time it would take to inflate the balloon to approximately two-thirds of its maximum volume ≈ 46.90 minutes.

4 0
3 years ago
6th grade math help me pleaseee
sveta [45]

Answer:

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7 0
3 years ago
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A parabola has a vertex of (3, 6) and passes through the point (1, 42).
hoa [83]
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