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andre [41]
3 years ago
5

If two numbers represent by (2m + 1) and (2m + 5) have a sum of 74, find

Mathematics
1 answer:
Pavel [41]3 years ago
5 0

(2m + 1) + (2m + 5) = 74

combine like terms

4m+6 = 74

subtract 6 from each side

4m = 68

divide by 4

m =17

2m+1 = 2(17)+ 1 = 34+1 = 35

2m+5 = 2(17) +5 = 34+5 = 39

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In a triangle when an angle between two equal length sides is 60 that means that the triangle is equilateral.
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<h3>Answer:</h3>

The Slope is 2

<h2>Explanation:</h2>

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<h3>Calculating for the slope of the line:</h3>

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Answer:

y_c = 2 + 10*x

Step-by-step explanation:

Given:

                                                y'' = 0

Find:

- The solution to ODE such that y(0) = 2, y'(0) = 10

Solution:

- Assuming a solution y = Ce^(mt)

So,                                y' = C*me^(mt)

                                    y'' = C*m^2e^(mt)

- Back substitute into given ODE, we get:

                                    y'' = C*m^2e^(mt) = 0

                                    e^(mt) can not be equal to zero

- Hence,                       m^2 = 0

                                     m = 0 , 0 - (repeated roots)

- The complimentary function for repeated roots is:

                                    y_c = (C1 + C2*x)*e^(m*t)

                                    y_c = C1 + C2*x  

- Evaluate @ y(0) = 2

                                    2 = C1 + C2*0

                                    C1 = 2

-Evaluate @ y'(0) = 10

                                    y'(t) = C2 = 10

Hence,                         y_c = 2 + 10*x

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