All categories

3 years ago

HELP PLEASEEEEEEEEEEEEEEEEEEEEEEEE

Mathematics

1 answer:

sasho [114]3 years ago

7 0

Answer:

9..........................................................

Step-by-step explanation:

You might be interested in

Solve the equation,<br> х<br> - 4 = – 15, for the given variable.<br> Answer: x =

Fed [463]

Answer:-11

Step-by-step explanation: add -4 to both sides which gives you -11.

4 0

3 years ago

Solve for x, 17x > -17

Sveta_85 [38]

Answer:

x = -1

Step-by-step explanation:

17x > -17, Divide both sides by 17

17x / 17 > -17 / 17

x > -1

5 0

3 years ago

Seven less than the product of a number n and

SVETLANKA909090 [29]

Answer:

(n-7) ≤ 95

Step-by-step explanation:

We need to write the expression for the given statement.

Seven less than the product of a number n and 1 means (n-7).

It is no more than 95. No more than 95 means less than or equal to i.e.

(n-7) ≤ 95

Hence, the above inequality shows the given statement.

5 0

3 years ago

If a person picks a pair of different Months, what is the probability that both months (different) have less than 31 days?

wlad13 [49]

Answer:

15.15% probability that both months (different) have less than 31 days.

Step-by-step explanation:

A probability is the number of desired outcomes divided by the number of total outcomes.

Also, the order of the months is not important. For example, picking July and August is the same as picking August and July. So the combinations formula is used to solve this problem

Combinations formula:

$C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

There are 12 months, of which February, April, June, September and November, that is, 5 of them, have less than 31 months.

Desired outcomes:

Picking 2 months from a set of 5(those with less than 31 days). So

$D = C_{5,2} = \frac{5!}{2!(3)!} = 10$

Total outcomes:

Picking 2 months from a set of 12(all the months). So

$T = C_{12,2} = \frac{12!}{2!(10)!} = 66$

Probability:

$P = \frac{10}{66} = 0.1515$

15.15% probability that both months (different) have less than 31 days.

5 0

3 years ago

A segment in the complex plane has a midpoint at 3 – 2i. If one endpoint of the segment is at 7 i, what is the other endpoint? –

Brut [27]

The midpoint of a segment divides the segment into equal halves

The other endpoint is 1- 5i

<h3>How to determine the missing endpoint </h3>

The coordinates are given as:

Point 1: 7 + i

Midpoint: 3 - 2i

Represent the other endpoint with x.

So, we have:

2 * Midpoint = Point 1 + x

This gives

$2 * (3 - 2i) =7 + i + x$

$6 - 4i =7 + i + x$

Collect like terms

$x = 6 -7- 4i -i$

Evaluate the like terms

$x = 1- 5i$

Hence, the other endpoint is 1- 5i