Answer: It took 18 Months for Michelle to collect 59 dolls.
Explanation:
First, let’s right an equation for this. Michelle started with 5 dolls in a bar collection (I have no clue what that is but i’ll roll with it), and each month she bought 3 more, so 5 dolls plus the 3 dolls per month equals 59 at some point.
5 dolls + 3 dolls per month = 59 dolls
OR
5 + 3m = 59
The point of this question is to find how many months (m) it took in order to get to 59 dolls and there’s multiple ways you can do this:
1) just plug in random numbers into m to see how long it takes to get to 59 [this option might take a while]
2) Try to isolate m (get every number out of the equation) to find out the value of m. [I’m most familiar with this way]
First, subtract 5 from 5 in the equation in order to get rid of it, since we’re trying to get all whole numbers out of the equation and only have m left. You subtract 5 from 59 since the equal sign is kind of like a mirrror, whatever you do to one side you have to do to the other. So, 5-5 is 0, and 59- is 54.
Now you’re left with 3m=54. In order to isolate the m, divide 3 by 3 to get rid of the 3, then divide 54 by 3, which is 18.
In order to check your work, plug 18 into m just to see if it works or not:
5+3m=59 —-> 5+ 3(18)= 59
3 times 18 is 54, plus 5 is 59. So, Mi hells took 18 months to collect her 59 dolls. Hope this helped!
Vertex coordinates: (h, k)
Vertex form: y = a(x-h)^2 + k
y = 2(x+3) + 2(x+4)
Use distributive property:
y = 2((x+3)+(x+4))
Simplify:
y = 2(2x+7)
y = 4x+14
This is slope - intercept form, not vertex form. Vertex form is for quadratic equations - this is a linear equation.
Answer (in slope - intercept form):
y = 4x+14
Answer:
isosceles
x=14
Step-by-step explanation:
isosceles because of the two I symbols on the triangle
x+5=2x-9
5+9=2x-x
14=x
Answer:
A college student took 4 courses last semester. His final grades, along with the credits each class is worth, are as follow: A (3), B (4), C (2), and D (3). The grading system assigns quality points as follows: A: 4; B: 3; C: 2; D: 1; and F: 0. Find the student’s GPA for this semester. Round your answer to the nearest thousandth.
another way is
This is a weighted average question. You are going to "weight" each course by the number of credits it is worth and then divide by the total number of credits. In other words, you are going to multiply each grade (A=4, B=3) by the number of credits attached to that grade. This will ensure that the courses that have more credits count more in the overall average. Then you are going to divide by the total number of credits to get the overall GPA.
So,
(3*4 + 4*3 + 2 *2 + 3*1)/(3+4+2+3) = GPA
Step-by-step explanation:
bran-list please
