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gladu [14]
3 years ago
8

Find the volume of a cylinder with a diameter of 16 m and a height of 8 m.

Mathematics
1 answer:
timama [110]3 years ago
6 0
It would be 6430.72 m3 would be your answer
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Solve with solution...no spam answers pls
Agata [3.3K]
<span>Let's analyze Hannah's work, step-by-step, to see if she made any mistakes. 

</span>In Step 1, Hannah wrote \dfrac{d}{dx} (-3+8x) <span> as the sum of two separate derivatives </span>\dfrac{d}{dx}(-3)+ \dfrac{d}{dx} (8x) <span>using the </span><span>sum rule.
</span>
This step is perfectly fine. 

In Step 2, \dfrac{d}{dx}(8x) was kept as it is, and \dfrac{d}{dx}(-3) was rewritten as 0 using the constant rule.Indeed, according to the constant rule, the derivative of a constant number is equal to zero.

This step is perfectly fine. 

In Step 3, \dfrac{d}{dx} (8x)  was rewritten as \dfrac{d}{dx}(8) \dfrac{d}{dx}(x) supposedly using the constant multiple rule.

The problem is that according to the constant multiple rule, \dfrac{d}{dx}(8x)&#10; should be rewritten as 8 \dfrac{d}{dx}(x) and not as \dfrac{d}{dx}(8)\dfrac{d}{dx}(x).  

<span>Therefore, Hannah made a mistake in this step.</span>
6 0
3 years ago
Read 2 more answers
This is the graph of y=x^2+2x-2 what is the range of this function
Sedaia [141]
The range is [-3, ∞)
3 0
3 years ago
What is the least common denominator of 4/x * -4/2x^2?
Vanyuwa [196]
The least common denominator would be 2x^2
that is because you would have to multiply the first fraction by 2x
but you can't just somehow simplify 2x^2, it wouldn't be right
4/x * -4/2x^2
2x*4/(2x*x) * -4/2x^2
8x /2x^2 * -4/2x^2
Then you would complete it 

Hope this helps :)
6 0
2 years ago
Read 2 more answers
30 miles per hour is how many feet per second?
Kisachek [45]

Answer: The answer is 44

8 0
3 years ago
If the areas of the given pairs of shapes are equal, find the value of x.​
den301095 [7]

Answer:

x = 8cm

Step-by-step explanation:

we are given a square and rectangle.we want to figure out x which is the width of the rectangle. we are also given a condition i.e

  • the area of the square equal to the area of the rectangle

therefore,

\displaystyle \rm A _{square } = A _{rect}

recall the formula of the area of square and rectangle so,

\displaystyle  {s}^{2} = lw

now assign variables

  • s \implies16cm
  • l \implies32cm
  • w \implies x

thus substitute:

\displaystyle 32cmx =  {16cm}^{2}

simplify square:

\displaystyle 32cmx = 256cm^2

divide both sides by 32:

\displaystyle  \boxed{x = 8cm}

and we're done!

3 0
2 years ago
Read 2 more answers
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