F(1) = 1^3 + 3(1)^1 - 3 - 1 = 1 + 3 - 3 - 1 = 0
so one zero is x = 1, and x-1 is a factor
dividing f(x) by x - 1 gives x^2 + 4x + 1
x = [-4 +/- sqrt (16 - 4)] / 2
x = -0.27, -3.73
zeroes are 1 , -0.27 and -3.73 Answer
Answer:
the function represnted in the table is linear
Step-by-step explanation:
Where's the digit?????????
