Subtract c and then x = y - c
And that's it!
If the problem is supposed to read (4^33*8^37)/(4^15*8^21), then...
(4^33*8^37)/(4^15*8^21) = (4^33/4^15)*(8^37/8^21)
(4^33*8^37)/(4^15*8^21) = 4^(33-15)*8^(37-21)
(4^33*8^37)/(4^15*8^21) = 4^18*8^16
Answer: Choice A) 4^18*8^16
Answer:
B 2 < x < 6
Step-by-step explanation:
six times an integer is between 12 and 36. Between does not include so we use < not ≤
12 < 6x < 36
Divide all sides by 6
12/6 < 6x/6 < 36/6
2 < x < 6
Answer:
3/5
Step-by-step explanation:
Soh Cah Toa
In some trigonometry classes, this acronym is very important to solving questions like this.
Why?
It tells us the right triangle-definition of these trigonometry functions.
We have that cosine of an angle is equal to tge side that is adjacent to it over the hypotenuse.
So here we are asked to find cos(B).
Lets look at triangle respect to the angle B
The measurement of the side that is opposite is 64.
The measurement of the side that is adjacent is 48.
The measurement of the hypotenuse is 80.
So cos(B)=48/80.
Let's reduce. 48 and 80 have a common factor of 8 so divide numerator and dexter by 8. This gives us:
cos(B)=6/10.
One more step in reducing. Both factors are even so cos(B)=3/5.
