2) Which equation has the same y-intercept as the graph on the right?

Rewrite in simplest terms: -8(-10u+6u-7)-10u−8(−10u+6u−7)−10u

Jobisdone [24]

Answer:

44u + 112

Step-by-step explanation:

5 0

3 years ago

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6.025 (25 is repeating) as a mixed number

Mashutka [201]

Answer:

6.025 as a mixed number is 6 1/40

3 0

3 years ago

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Write an equation of the line in slope- intercept form

gavmur [86]

Answer:

$a)\ y=-\frac{1}{3}x$

Step-by-step explanation:

Slope (m) form: $\frac{y_2-y_1}{x_2-x_1}$

$m=\frac{y_2-y_1}{x_2-x_1} \\\\m=\frac{1-0}{-3-0} \\\\m=\frac{1}{-3} \\\\m=-\frac{1}{3}$

$y=mx+b\\y=-\frac{1}{3}x +b$

(0, 0)

$y=-\frac{1}{3}x +b\\0=-\frac{1}{3}(0) +b\\0=0+b\\0=b$

$y=-\frac{1}{3}x +0\\y=-\frac{1}{3}x$

Check your answer:

$y=-\frac{1}{3}x \\1=-\frac{1}{3}(-3)\\1=-1$

This statement is true

Hope this helps!

6 0

2 years ago

An automobile owner found that 20 years ago, 72% of Americans said that they would prefer to purchase an American automobile. He

LenaWriter [7]

Answer:

$z=\frac{0.884 -0.72}{\sqrt{\frac{0.72(1-0.72)}{43}}}=2.395$

Now we can find the p value taking incount that we are using a bilateral test

$p_v =2*P(z>2.395)=0.01662$

Since the p value is lower than the significance level of 0.1 we have enough evidence to reject the null hypothesis and we can conclude that the true proportion of Americans that they would prefer an American automobile is significantly different from 0.72 and then the claim is correct

Step-by-step explanation:

Information given

n=43 represent the random sample taken

X=38 represent the Americans who they would prefer an American automobile

$\hat p=\frac{38}{43}=0.884$ estimated proportion of Americans that they would prefer an American automobile

$p_o=0.72$ is the value that we want to check

$\alpha=0.1$ represent the significance level

z would represent the statistic

$p_v$ represent the p value

Hypothesis to test

We want to verify if the percentage of Americans that they would prefer an American automobile today differs from 72%, then the system of hypothesis are:

Null hypothesis: $p=0.72$

Alternative hypothesis: $p \neq 0.72$

The statistic is given by:

$z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}}$ (1)

Replacing the data given we got:

$z=\frac{0.884 -0.72}{\sqrt{\frac{0.72(1-0.72)}{43}}}=2.395$

Now we can find the p value taking incount that we are using a bilateral test

$p_v =2*P(z>2.395)=0.01662$

Since the p value is lower than the significance level of 0.1 we have enough evidence to reject the null hypothesis and we can conclude that the true proportion of Americans that they would prefer an American automobile is significantly different from 0.72 and then the claim is correct

5 0

3 years ago

Juliet is being tested for a contagious disease. The test is 99% accurate and in actuality 0.1% of the population has the diseas

Fed [463]

The answers A and C contain correct information but both of them provide different advice. so the answer is literally your opinion between a and c

7 0

4 years ago

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