Find the zeros of the function by rewriting in intercept form.

1 answer:

8 0

The intercept form is $y=a(x-p)(x-q)$ where p, q - the zeroes of a function.

1.
$y=2x^2-4x \\
y=2x(x-2) \\
y=2(x-0)(x-2) \\
\hbox{the zeroes - }\boxed{x=0 \ and \ x=2}$

2.
$y=2x^2-11x-21 \\
y=2x^2-14x+3x-21 \\
y=2x(x-7)+3(x-7) \\
y=(2x+3)(x-7) \\
y=2(x+\frac{3}{2})(x-7) \\ y=2(x-(-\frac{3}{2}))(x-7) \\
\hbox{the zeroes - }\boxed{x=-\frac{3}{2} \ and \ x=7}$

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