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denis23 [38]
3 years ago
6

Find the zeros of the function by rewriting in intercept form.

Mathematics
1 answer:
Naddika [18.5K]3 years ago
8 0
The intercept form is y=a(x-p)(x-q) where p, q - the zeroes of a function.

1.
y=2x^2-4x \\
y=2x(x-2) \\
y=2(x-0)(x-2) \\
\hbox{the zeroes - }\boxed{x=0 \ and \ x=2}

2.
y=2x^2-11x-21 \\
y=2x^2-14x+3x-21 \\
y=2x(x-7)+3(x-7) \\
y=(2x+3)(x-7) \\
y=2(x+\frac{3}{2})(x-7) \\ y=2(x-(-\frac{3}{2}))(x-7) \\
\hbox{the zeroes - }\boxed{x=-\frac{3}{2} \ and \ x=7}
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for the decimal 0.555 the value of the digit in the tens place is how many times as much as the value of the digit in the thousa
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Answer:

4

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Yuliya22 [10]
Let x and y be the rate per hour for Mechanic 1 and 2 respectively.

Then,
x+y=205 ---------- (1)
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10x+10y = 2050
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----------------------
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3 years ago
Find the solutions of the quadratic equation -9c² +2 +3 = 0.
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Given that,

An equation : -9c² +2c +3 = 0

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Find the value of x.

Solution,

We have, -9c² +2c +3 = 0

We can solve it using the formula as follows :

x=\dfrac{-b\pm \sqrt{b^2-4ac}}{2a}

Here, a = -9, b = 2 and c =3

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