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vlabodo [156]
3 years ago
8

Can someone explain how these equal 5 and -5 please

Mathematics
1 answer:
uysha [10]3 years ago
6 0
I'm not sure how you obtained -5 as your answer but this is the mathematical explanation. hope this helps!
{x}^{2}  + 3x = 40 \\  {x}^{2}  + 3x - 40 = 0 \\(x + 8)(x - 5) = 0 \\ x =  - 8 \\ x = 5
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What is the value of 2xy if x = 3 and y = 2
romanna [79]
Substitute the values.
2(3)(2)=?
2*3=6
6*2=12
Final answer: 12
8 0
3 years ago
Read 2 more answers
<img src="https://tex.z-dn.net/?f=%28%20%5Cfrac%7B1%7D%7B2%7D%29%5E%7B2%7D%20" id="TexFormula1" title="( \frac{1}{2})^{2} " alt=
Vladimir79 [104]
All you need to do is solve it
\frac{1}{2} ^{2} or \frac{1}{2}  x \frac{1}{2}
When solved your answer is 0.25 or 1/4
------------------------
What I did to solve it was....

1. Divide top fraction by bottom fraction to get decimal
1 ÷ 2 = 0.5

2. Then multiply 0.5 by its self (the same as putting it to the ^2)
0.5 x 0.5 = 0.25
5 0
3 years ago
Factor the trinomial<br><br> X2-12x +16
wlad13 [49]
2*&/45/+=67364/3/4/32:5,6544 is hothead answer
6 0
3 years ago
A student claims that 8^3 x 8^-5 is greater than 1. Explain whether the student is correct or not.
nlexa [21]
Remember:
a^m * a^n=a^(m+n)
a^-m=1/a^m


8³ x 8⁻⁵=8³⁻⁵=8⁻²=1/8²=1/64<1

Answer: the student is not correct, because 1/64<1, and 8³ x 8⁻⁵=1/64.
7 0
3 years ago
Suppose that the population mean for income is $50,000, while the population standard deviation is 25,000. If we select a random
Fudgin [204]

Answer:

Probability that the sample will have a mean that is greater than $52,000 is 0.0057.

Step-by-step explanation:

We are given that the population mean for income is $50,000, while the population standard deviation is 25,000.

We select a random sample of 1,000 people.

<em>Let </em>\bar X<em> = sample mean</em>

The z-score probability distribution for sample mean is given by;

               Z = \frac{\bar X-\mu}{\frac{\sigma}{\sqrt{n} } }  ~ N(0,1)

where, \mu = population mean = $50,000

            \sigma = population standard deviation = $25,000

            n = sample of people = 1,000

The Z-score measures how many standard deviations the measure is away from the mean. After finding the Z-score, we look at the z-score table and find the p-value (area) associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X.

So, probability that the sample will have a mean that is greater than $52,000 is given by = P(\bar X > $52,000)

  P(\bar X > $52,000) = P( \frac{\bar X-\mu}{\frac{\sigma}{\sqrt{n} } } > \frac{52,000-50,000}{\frac{25,000}{\sqrt{1,000} } } ) = P(Z > 2.53) = 1 - P(Z \leq 2.53)

                                                                    = 1 - 0.9943 = 0.0057

<em>Now, in the z table the P(Z </em>\leq<em> x) or P(Z < x) is given. So, the above probability is calculated by looking at the value of x = 2.53 in the z table which has an area of 0.9943.</em>

Therefore, probability that the sample will have a mean that is greater than $52,000 is 0.0057.

5 0
2 years ago
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