Let n be the larger integer and n-2 be the smaller integer.
n² - (n - 2)²
= n² - (n - 2)(n - 2)
= n² - (n² - 4n - 4)
= n² - n² + 4n + 4
= 4n + 4
= 4(n + 1)
No matter what value n is, it will always be a multiple of 4.
Answer:
(13/2,-5/2)
Step-by-step explanation:
I hope this helps
Answer:
6.4
Step-by-step explanation:
formula: √(X2-X1)²+(Y2-Y1)²
hope it helps!
the answer is 4.8. Your welcome
Answer:
3
Step-by-step explanation:
three