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ladessa [460]
2 years ago
13

SV is angle bisector of

Mathematics
1 answer:
DochEvi [55]2 years ago
8 0

Answer:

<h3>Sv is angle bisector of rst.</h3>
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2 years ago
Please I really need help on this!<br>​
Svetradugi [14.3K]

Step-by-step explanation:

output is 3 times of input so it's like this x ➡ 3x

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3 years ago
Find the median: <br>17, 25, 35, 22, 31, 12, 17​
Pachacha [2.7K]

Answer:

22

Step-by-step explanation:

The median of a data set is found by putting the data set in ascending numerical order and identifying the middle number. If there are an odd number of data values in the data set, the median is a single number. If there are an even number of data values in the data set, the median is the average of the two middle numbers. Sorting the data set for the values entered above we have:

12,   17,   17,   22,   25,   31,   35

Since there is an odd number of data values in this data set, there is only one middle number. With 7 data values, the middle number is the data value at position 4. Therefore, the median is 22.

7 0
2 years ago
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Am I correct? Just check please
creativ13 [48]

Answer:

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Step-by-step explanation:

|Wow! Nice Job! Even though Absolute value is EXTREMELy EASY you probably aced the test!

6 0
2 years ago
Doug hits a baseball straight towards a 15 ft high fence that is 400 ft from home plate. The ball is hit 2.5ft above the ground
Scorpion4ik [409]

Answer:

125.4\ \text{m/s}

Step-by-step explanation:

u = Initial velocity of baseball

\theta = Angle of hit = 30^{\circ}

x = Displacement in x direction = 400 ft

y = Displacement in y direction = 15 ft

y_0 = Height of hit = 2.5 ft

a_y = g = Acceleration due to gravity = 32.2\ \text{ft/s}^2

t = Time taken

Displacement in x direction

x=u_xt\\\Rightarrow x=u\cos\theta t\\\Rightarrow t=\dfrac{x}{u\cos\theta}\\\Rightarrow t=\dfrac{400}{u\cos30^{\circ}}\\\Rightarrow t=\dfrac{400}{u\dfrac{\sqrt{3}}{2}}\\\Rightarrow t=\dfrac{800}{u\sqrt{3}}

Displacement in y direction

y=y_0+u_yt+\dfrac{1}{2}a_yt^2\\\Rightarrow y=y_0+u\sin\theta t+\dfrac{1}{2}a_yt^2\\\Rightarrow 15=2.5+u\sin30^{\circ}(\dfrac{800}{u\sqrt{3}})+\dfrac{1}{2}\times -32.2\times (\dfrac{800}{u\sqrt{3}})^2\\\Rightarrow \dfrac{400}{\sqrt{3}}-\dfrac{10304000}{3u^2}-12.5=0\\\Rightarrow 218.44=\dfrac{10304000}{3u^2}\\\Rightarrow u=\sqrt{\dfrac{10304000}{3\times218.44}}\\\Rightarrow u=125.4\ \text{m/s}

The minimum initial velocity needed for the ball to clear the fence is 125.4\ \text{m/s}

5 0
3 years ago
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