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Answer:
I assume you know Arithmetic Progression .
so, we have to find the first and last 4-digit number divisible by 5
first = 1000 , last = 9990
we have a formula, = a + (n-1)d
here, is the last 4-digit number divisible by 5.
n is the number of 4-digit even numbers divisible by 5
d is the common difference between the numbers, which is 10 in this case
a is the first 4-digit number divisible by 5
9990 = 1000 + (n-1)*10
899 = n-1
n = 900
Hence, there are 900 4-digit even numbers divisible by 5
Step-by-step explanation: Standard form is when we take a polynomial and we write it in order from the greatest degree to the smallest degree.
Let's look at an example which I provided in the image attached.
In this polynomial, I have 2 degrees, 1 degree, and 1 degree above the <em>x</em>.
This is not in the form of least to greatest so I need to write it in descending order. Our constant which in this is 27 will be last in polynomial.
So, you look at the degree of each term and then write each in term in order of degree from greatest to least (descending order).
