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3 years ago

If you pay your bills on time, stay within your limit, and pay more than the

Mathematics

1 answer:

ser-zykov [4K]3 years ago

5 0

Answer:

Your credit score increases.

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If you want mark me brainlest, but you don't have to

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Someone help me do the first problem so that I can do the rest

Novay_Z [31]

Answer:

C = 69.1 ft

Step-by-step explanation:

The circumference is given by

C = 2*pi*r

C = 2* 3.14 * 11

C =69.08

Round to the nearest tenth

C = 69.1 ft

7 0

3 years ago

What is the product of 16x48?

Elis [28]

768 because 6x8 = 48 the 8 drop Down to the answer and the 4 on top of 1 and multiply 1x8= 8+1 =9 so the 9 drop down to the answer. Now that is fake because you need to multiply 4x6 and 4x1 so 4x6 is 24 below the 8 add a 0 and go 1 move to the left and put 4 and 2 on top of 1 now 4x1 is 4+1 is 5 and put 5 on the left of 4 and the final step is add 98+540=768 so 768 is your real answer.

4 0

3 years ago

If you had a bad day, Here is some free points.

OverLord2011 [107]

Answer:

thank you

Step-by-step explanation:

4 0

3 years ago

Read 2 more answers

A rose garden is formed by joining a rectangle and a semicircle, as shown below. The rectangle is 31 ft long and 20 ft wide. If

vekshin1

Answer:

133 ft

Step-by-step explanation:

Given in the question,

length of the rectangle = 31 ft

width of the rectangle= 20 ft

diameter of semicircle = 20 ft

radius of semicircle = 20/2 ft = 10 ft

Formula to use:

<h3>perimeter of rectangle + perimeter of semicircle</h3>

perimeter of rectangle = 2(l+w)

perimeter of semicircle = 1/2(2πr)

Plug values in the formula above

2(31 + 20) + 3.14(10)

133.4 ft

≈ 133 ft

7 0

3 years ago

The logistic equation for the population (in thousands) of a certain species is given by:

Eva8 [605]

Answer:

b. 1.5

c. 1.5

d. No

Step-by-step explanation:

a. First, let's solve the differential equation:

$\frac{dp}{dt} =3p-2p^2$

Divide both sides by $3p-2p^2$ and multiply both sides by dt:

$\frac{dp}{3p-2p^2}=dt$

Integrate both sides:

$\int\ \frac{1}{3p-2p^2} dp =\int\ dt$

Evaluate the integrals and simplify:

$p(t)=\frac{3e^{3t} }{C_1+2e^{3t}}$

Where C1 is an arbitrary constant

I sketched the direction field using a computer software. You can see it in the picture that I attached you.

b. First let's find the constant C1 for the initial condition given:

$p(0)=3=\frac{3e^{0} }{C_1+2e^{0} } =\frac{3}{C_1+2}$

Solving for C1:

$C_1=-1$

Now, let's evaluate the limit:

$\lim_{t \to \infty} \frac{3e^{3t} }{2e^{3t}-1 } \\\\Divide\hspace{3}the\hspace{3}numerator\hspace{3}and\hspace{3}denominator\hspace{3}by\hspace{3}e^{3t} \\\\ \lim_{t \to \infty} \frac{3 }{2-e^{-3x} }$

The expression $-e^{-3x}$ tends to zero as x approaches ∞ . Hence:

$\lim_{t \to \infty} \frac{3e^{3t} }{2e^{3t}-1 } =\frac{3}{2} =1.5$

c. As we did before, let's find the constant C1 for the initial condition given:

$p(0)=0.8=\frac{3e^{0} }{C_1+2e^{0} } =\frac{3}{C_1+2}$

Solving for C1:

$C_1=1.75$

Now, let's evaluate the limit:

$\lim_{t \to \infty} \frac{3e^{3t} }{2e^{3t}+1.75 } \\\\Divide\hspace{3}the\hspace{3}numerator\hspace{3}and\hspace{3}denominator\hspace{3}by\hspace{3}e^{3t} \\\\ \lim_{t \to \infty} \frac{3 }{2+1.75e^{-3x} }$

The expression $-e^{-3x}$ tends to zero as x approaches ∞ . Hence:

$\lim_{t \to \infty} \frac{3e^{3t} }{2e^{3t}+1.75 } =\frac{3}{2} =1.5$

d. To figure out that, we need to do the same procedure as we did before. So, let's find the constant C1 for the initial condition given:

$p(0)=2=\frac{3e^{0} }{C_1+2e^{0} } =\frac{3}{C_1+2}$

Solving for C1:

$C_1=-\frac{1}{2} =-0.5$

Can a population of 2000 ever decline to 800? well, let's find the limit of the function when it approaches to ∞:

$\lim_{t \to \infty} \frac{3e^{3t} }{2e^{3t}-0.5 } \\\\Divide\hspace{3}the\hspace{3}numerator\hspace{3}and\hspace{3}denominator\hspace{3}by\hspace{3}e^{3t} \\\\ \lim_{t \to \infty} \frac{3 }{2-0.5e^{-3x} }$

The expression $-e^{-3x}$ tends to zero as x approaches ∞ . Hence:

$\lim_{t \to \infty} \frac{3e^{3t} }{2e^{3t}-0.5 } =\frac{3}{2} =1.5$

Therefore, a population of 2000 never will decline to 800.

6 0

3 years ago