I suspect that the pressure of this change is constant therefore
The equation is used from the combined gas law. (When pressure is constant both P's will cancel out P/P = 1)
V/T = V/T
Initial Change
Initially we have 2L at 20 degress what temperature will be at 1L.
2/20 = 1/T
0.1 = 1/T
0.1T = 1
T = 1/0.1
T = 10 degress celsius.
Hope this helps if you won't be able to understand what is the combined gas law just tell me :).
Answer : The time passed in days is 28.6 days.
Explanation :
Half-life = 14.3 days
First we have to calculate the rate constant, we use the formula :
Now we have to calculate the time passed.
Expression for rate law for first order kinetics is given by:
where,
k = rate constant =
t = time passed by the sample = ?
a = let initial amount of the reactant = 100 g
a - x = amount left after decay process = 100 - 75.0 = 25.0 g
Now put all the given values in above equation, we get
Therefore, the time passed in days is 28.6 days.
Answer:
The answer is
<h2>1.20 g/mL</h2>
Explanation:
The density of a substance can be found by using the formula
From the question
mass of liquid = 138 g
volume = 115 mL
The density is
We have the final answer as
<h3>1.20 g/mL</h3>
Hope this helps you
Answer:
V = 34.3 L
Explanation:
Given data:
Volume of hydrogen produced = ?
Mass of magnesium = 36.7 g
Temperature and pressure = standard
Solution:
Mg + 2HCl → MgCl₂ + H₂
Number of moles of magnesium:
Number of moles = mass/molar mass
Number of moles = 36.7 g/ 24 g/mol
Number of moles = 1.53 mol
Now we will compare the moles of magnesium with hydrogen.
Mg : H₂
1 : 1
1.53 : 1.53
Number of moles of hydrogen produced = 1.53 mol
Volume of hydrogen:
PV = nRT
V = nRT / P
V = 1.53 mol × 0.0821 atm.L/mol.K × 273 K/ 1 atm
V = 34.3 L