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3 years ago

What is the name and formula of the compound formed between lithium and sulfite?

Chemistry

1 answer:

dmitriy555 [2]3 years ago

6 0

Answer:

d)Lithium sulfite, Li2SO3

Explanation:

LITHIUM is an element in the group 1 (alkali metals) of the periodic table, with a charge of +1. On the other hand, SULFITE is a radical with the chemical formula (SO3²-). It is made up of sulfur and oxygen atoms.

According to this question, lithium element and sulfite radical combines to form a compound called LITHIUM SULFITE. From the chemical formula of these individual constituents, the chemical formula of the compound formed will go this: Li2SO3. This means that it takes 2 atoms of Li+ to combine with SO3²- in order to form a neutral compound.

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3 years ago

Na + H2 → NaCl balanced equation

hodyreva [135]

Answer:

..............

........

.............

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2 years ago

Read 2 more answers

HELP PLEASE THE OTHER 'ANSWER' ISNT EVEN AN ANSWER!

hodyreva [135]

Answer:

most likely that (2) the replicated experiment was performed incorrectly.

Why, u ask? u dare question me:

1- The initial experiment invalidness cannot be proven.

2- the second answer is correct

3- Different labaratories does not effect the outcome, as long as the parameter and environment of the replicated experiment is the same as when the initial experiment was conducted.

4- Already knowing the data and errors would increase the precision of the replicated experiment.

5- Change in variables should still be in the objective (or purpose) of the experiment, thus, major difference in the outcome should not happen.

happy learning!

4 0

3 years ago

A student is asked to standardize a solution of barium hydroxide. He weighs out 0.978 g potassium hydrogen phthalate (KHC8H4O4,

Sav [38]

Answer:

(A) 0.129 M

(B) 0.237 M

Explanation:

(A) The reaction between potassium hydrogen phthalate and barium hydroxide is:

2HA + Ba(OH)₂ → BaA₂ + 2H₂O

Where A⁻ is the respective anion of the monoprotic acid (KC₈H₄O₄⁻).

We convert mass of phthalate to moles, using its molar mass:

0.978 g ÷ 156 g/mol = 9.27x10⁻³ mol = 9.27 mmol

Now we convert mmol of HA to mmol of Ba(OH)₂:

9.27 mmol HA * $\frac{1mmolBa(OH)_{2}}{2mmolHA}$ = 6.64 mmol Ba(OH)₂

Finally we calculate the molarity of the Ba(OH)₂ solution:

6.64 mmol / 35.8 mL = 0.129 M

(B) The reaction between Ba(OH)₂ and HCl is:

2HCl + Ba(OH)₂ → BaCl₂ + 2H₂O

So the moles of HCl that reacted are:

17.1 mL * 0.129 M * $\frac{2mmolHCl}{1mmolBa(OH)_2}$ = 4.41 mmol HCl

And the molarity of the HCl solution is:

4.41 mmol / 18.6 mL = 0.237 M

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3 years ago