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3241004551 [841]
3 years ago
15

How do I solve this?

Mathematics
2 answers:
Lorico [155]3 years ago
4 0

Answer:

x>\frac{83}{15}

Step-by-step explanation:

STEP 1: Simplify \frac{x-5}{2} +\frac{2}{5}>\frac{2}{3}

\frac{5x-21}{10}>\frac{2}{3}

STEP 2: Multiply both sides of the equation by 10.

\frac{5x-21}{10}>\frac{2}{3}*(10)

STEP 3: Remove parentheses.

\frac{5x-21}{10}>\frac{2}{3}*(10)

STEP 4: Multiply \frac{2}{3}*(10)

\frac{5x-21}{10}>\frac{20}{3}

STEP 5: Move all terms not containing x to the right side of the inequality.

5x>\frac{83}{3}

STEP 6: Divide each term by 5 and simplify.

x>\frac{83}{15}

STEP 7: The result can be shown in multiple forms.

Inequality Form:

x>\frac{83}{15}

Interval Notation:

(\frac{83}{15},∞)

Advocard [28]3 years ago
4 0

Answer:

x > \frac{83}{15}

Step-by-step explanation:

Given

\frac{x-5}{2} + \frac{2}{5} > \frac{2}{3}

Multiply through by 30 ( the LCM of 2, 5 and 3 ) to clear the fractions

15(x - 5) + 12 > 20 ← distribute and simplify left side

15x - 75 + 12 > 20

15x - 63 > 20 ( add 63 to both sides )

15x > 83 ( divide both sides by 15 )

x > \frac{83}{15}

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