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Ilia_Sergeevich [38]
3 years ago
14

Exam Guidelines

Mathematics
2 answers:
KiRa [710]3 years ago
6 0

Answer:

B. y = 31

Step-by-step explanation:

Subtract 228 from both sides

4y + 228 - 228 = 352 - 228

4y = 124

Divide both sides by 4 to solve for y

4y / 4 = 124 / 4

y = 31

pashok25 [27]3 years ago
4 0

Answer:

Answer is B. Y=31

Step-by-step explanation:

4y + 228 = 352

(4)(y) = 352 -228

y = 124/4

y = 31

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Let (6,-5) be a point on the terminal side of θ. Find the exact values of sin θ, sec θ, and tan θ.
makvit [3.9K]

Answer:

sinθ = -5/√61

secθ = √61/6

tanθ = -5/6

Step-by-step explanation:

From the given coordinate (6, -5), x = 6 and y = -5. This shows that the point lies in the 4th quadrant. In the fourth quadrant, only cos θ is positive, both sin θ and tan θ are negative.

Let us get the value of the radius 'r' first before calculating the trigonometry identities.

Using the Pythagoras theorem;

r^2 = x^2 + y^2\\r^2 = 6^2 + (-5)^2\\r^2 = 36+25\\r^2 = 61\\r = \sqrt{61}

Using SOH, CAH, TOA to get the trigonometry identities;

Given x = 6, y =5 and r = √61

sin \theta = opp/hyp = y/r\\sin \theta = 5/\sqrt{61} \\

Since sin θ, is negative in the fourth quadrant, sin \theta = -5/\sqrt{61} \\

cos \theta = adj/hyp = x/r\\cos \theta = 6/\sqrt{61} \\

sec \theta = \frac{1}{cos \theta} \\sec \theta = \frac{1}{6/\sqrt{61}  } \\sec \theta = \frac{\sqrt{61} }{6}

For tanθ:

tan \theta = \frac{opp}{adj} = \frac{y}{x}  \\tan \theta = \frac{5}{6}\\

Since tan θ, is negative in the fourth quadrant, tan \theta = -5/6

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Step-by-step explanation:

Use the slope formula to find the slope.

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