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asambeis [7]
3 years ago
5

I need help lol.. what is a solution to this equation: y = -1/4x + 8

Mathematics
1 answer:
BlackZzzverrR [31]3 years ago
5 0

Answer:

You cannot solve this

Step-by-step explanation:

you need at least one value given like x=something or y=something so you can plug it in

if you meant solve for x, then x= -4y+32

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Please help will give brainliest!
Ipatiy [6.2K]

Answer:

Should be 1 if im not wrong Then Mark Me brainliest

Step-by-step explanation:

a negative times a neg equals a posative

Neg x pos = neg

pos x neg = neg

pos x pos = pos

neg x neg = pos

so if there greater then over neg<, >,=

You would look at the problem for given f(x)=

x → -1 and neg times neg more or less

-1 x -1 = 1

7 0
3 years ago
Apply properties of operatione to write an equivalent expression​
____ [38]

Answer:

4t

Step-by-step explanation:

All we are doing is combining like terms and since all of then have a "t" in it we would just add the 4 "t's" together like normal addition.

4 0
3 years ago
Write an equation of the hyperbola given that the center is at (2, -3), the vertices are at (2, 3) and (2, - 9), and the foci ar
zavuch27 [327]
Check the picture below.

so, the hyperbola looks like so, clearly a = 6 from the traverse axis, and the "c" distance from the center to a focus has to be from -3±c, as aforementioned above, the tell-tale is that part, therefore, we can see that c = 2√(10).

because the hyperbola opens vertically, the fraction with the positive sign will be the one with the "y" in it, like you see it in the picture, so without further adieu,

\bf \textit{hyperbolas, vertical traverse axis }&#10;\\\\&#10;\cfrac{(y- k)^2}{ a^2}-\cfrac{(x- h)^2}{ b^2}=1&#10;\qquad &#10;\begin{cases}&#10;center\ ( h, k)\\&#10;vertices\ ( h,  k\pm a)\\&#10;c=\textit{distance from}\\&#10;\qquad \textit{center to foci}\\&#10;\qquad \sqrt{ a ^2 + b ^2}\\&#10;asymptotes\quad  y= k\pm \cfrac{a}{b}(x- h)&#10;\end{cases}\\\\&#10;-------------------------------

\bf \begin{cases}&#10;h=2\\&#10;k=-3\\&#10;a=6\\&#10;c=2\sqrt{10}&#10;\end{cases}\implies \cfrac{[y- (-3)]^2}{ 6^2}-\cfrac{(x- 2)^2}{ b^2}=1&#10;\\\\\\&#10;\cfrac{(y+3)^2}{ 36}-\cfrac{(x- 2)^2}{ b^2}=1&#10;\\\\\\&#10;c^2=a^2+b^2\implies (2\sqrt{10})^2=6^2+b^2\implies 2^2(\sqrt{10})^2=36+b^2&#10;\\\\\\&#10;4(10)=36+b^2\implies 40=36+b^2\implies 4=b^2&#10;\\\\\\&#10;\sqrt{4}=b\implies 2=b\\\\&#10;-------------------------------\\\\&#10;\cfrac{(y+3)^2}{ 36}-\cfrac{(x- 2)^2}{ 2^2}=1\implies \cfrac{(y+3)^2}{ 36}-\cfrac{(x- 2)^2}{ 4}=1

3 0
3 years ago
Kevin asked his trainee, Anna, to help call some of his clients to sell a newly-issued municipal bond. If he had to call all of
weqwewe [10]

Answer:

3.6 hours

Step-by-step explanation:

To solve, create a Rate, Time, Work chart:

Work is rate times time. For Kevin, his work is going to equal x over 6 job. For Anna, her expression for work will equal x over 9 job.

The work is 1 job of calling all clients, so their combined work is equal to 1.  

x over 6 plus x over 9 equals 1

In the rational equation, x is the amount of time it takes Kevin and Anna to call the clients together.  With rational equations, the terms can be added together once they have common denominators.  

x over 6 plus x over 9 equals 1

fraction numerator begin display style x left parenthesis 9 right parenthesis end style over denominator begin display style 6 left parenthesis 9 right parenthesis end style end fraction plus fraction numerator begin display style x left parenthesis 6 right parenthesis end style over denominator begin display style 9 left parenthesis 6 right parenthesis end style end fraction equals fraction numerator begin display style 1 left parenthesis 6 right parenthesis left parenthesis 9 right parenthesis end style over denominator left parenthesis 6 right parenthesis left parenthesis 9 right parenthesis end fraction

fraction numerator 9 x over denominator 54 end fraction plus fraction numerator 6 x over denominator 54 end fraction equals 54 over 54

9 x plus 6 x equals 54

15 x equals 54

x equals 3.6

If Kevin and Anna work together, they can call all the clients in 3.6 hours.

7 0
3 years ago
Can someone please help me with this question?
dimulka [17.4K]
Answer: Hahahhahahaha


Explanation:

Ihwhwbwbajbwbausbw ahjw
6 0
3 years ago
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