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Genrish500 [490]

2 years ago

7

GIVEING BRALIST

2 answers:

USPshnik [31]2 years ago

6 0

<h2>Answer:</h2>

A GIRL ON HERE NAMED SAMI32390

<h2>Step-by-step explanation:</h2>

amm18122 years ago

6 0

Answer:

Hmmm, this is a hard question loll. I would say my mom because she is always there for me when I’m in need. Also because if It wasn’t for her, there wouldn’t be me today.

Step-by-step explanation:

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What is the surface area of these cuboids?

Dafna1 [17]

Answer:

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Which number below has a value between 6.6 and 6.7?

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Step-by-step explanation:

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3 years ago

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Find the new amount given the original amount and the percent of change.

QveST [7]

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3 years ago

Why is the answer to this integral's denominator have 1+pi^2

ss7ja [257]

It comes from integrating by parts twice. Let

$I = \displaystyle \int e^n \sin(\pi n) \, dn$

Recall the IBP formula,

$\displaystyle \int u \, dv = uv - \int v \, du$

Let

$u = \sin(\pi n) \implies du = \pi \cos(\pi n) \, dn$

$dv = e^n \, dn \implies v = e^n$

Then

$\displaystyle I = e^n \sin(\pi n) - \pi \int e^n \cos(\pi n) \, dn$

Apply IBP once more, with

$u = \cos(\pi n) \implies du = -\pi \sin(\pi n) \, dn$

$dv = e^n \, dn \implies v = e^n$

Notice that the ∫ v du term contains the original integral, so that

$\displaystyle I = e^n \sin(\pi n) - \pi \left(e^n \cos(\pi n) + \pi \int e^n \sin(\pi n) \, dn\right)$

$\displaystyle I = \left(\sin(\pi n) - \pi \cos(\pi n)\right) e^n - \pi^2 I$

$\displaystyle (1 + \pi^2) I = \left(\sin(\pi n) - \pi \cos(\pi n)\right) e^n$

$\implies \displaystyle I = \frac{\left(\sin(\pi n) - \pi \cos(\pi n)\right) e^n}{1+\pi^2} + C$

6 0

2 years ago

HELP!!!!!!!!!!!!!!! 15 POINTS

disa [49]

$60 for 2 hours and $100 in total for 2 hours of work and the service fee

3 0

3 years ago