All categories

3 years ago

Please give all the steps, and i will chose brainliest

Mathematics

1 answer:

Ghella [55]3 years ago

7 0

Answer:

ok so you have to see if its the right triangle, so basicaly like count the squares on the triangle. It may be the right triangle cause all triangle are the same, just up side down, etc.

Step-by-step explanation:

But its not the right triangle, theres no points at the end.

sorry if its not right!

You might be interested in

Which of these people need to buy renters insurance?

olganol [36]

C Amy, who uses a rented car

7 0

3 years ago

Read 2 more answers

Find all exact solutions on the interval [0, 2π). Look for opportunities to use trigonometric identities.

Nostrana [21]

Answer:

x = π/2, 7π/6, or 11π/6

Step-by-step explanation:

sin² x − cos² x − sin x = 0

Use Pythagorean identity to write cosine in terms of sine.

sin² x − (1 − sin² x) − sin x = 0

sin² x − 1 + sin² x − sin x = 0

2 sin² x − sin x − 1 = 0

Factor:

(2 sin x + 1) (sin x − 1) = 0

Solve:

sin x = -1/2 or 1

x = π/2, 7π/6, or 11π/6

7 0

3 years ago

Read 2 more answers

An angle measures 12 degrees less than three times it's supplement. Find the measure of the angle.

Aleonysh [2.5K]

supplementary angles = 180 degrees

so x = angle 1

y = angle 2

y = 3x-12

x + 3x-12 =180

4x-12 = 180

4x = 192

x = 192/4 = 48

y = 3(48) -12 = 144-12 = 132

132 +48 = 180

the angle is 132

4 0

4 years ago

What is the meaning of zero in this situation: 9 degrees below 0

Aleksandr [31]

The meaning of it is this:
below 0 is stating negatives which are even smaller than zero

6 0

3 years ago

PLEASE HELP ME 40 PTS!!!!!!

SSSSS [86.1K]

Answer:

The sequence converges to infinity.

Step-by-step explanation:

$a_n = \frac{n^3 - n}{n^2 + 5n}\\\\ \lim_{n \to \infty} a_n = \lim_{n \to \infty} \frac{n^3 - n}{n^2 + 5n}$

$= \lim_{n \to \infty} \frac{n(n^2 - 1)}{n(n + 5)} \\\\= \lim_{n \to \infty} \frac{(n^2 - 1)}{(n + 5)}\\\\= \lim_{n \to \infty} \frac{n(n - \frac{1}{n})}{n(1 + \frac{5}{n})}\\\\= \lim_{n \to \infty} \frac{(n - \frac{1}{n})}{(1 + \frac{5}{n})}$

$denominator = \lim_{n \to \infty} 1 + \frac{5}{n} = 1 + \lim_{n \to \infty} \frac{5}{n} = 1+0 = 1$

$numerator = \lim_{n \to \infty} n - \frac{1}{n} = \infty$

Therefore,

$\lim_{n \to \infty} a_n = \frac{ \infty}{1} = \infty$

8 0

3 years ago