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Mathematics

1 answer:

lara31 [8.8K]3 years ago

5 0

300 because it simple

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The bending of a bean varies directly as its mas. A beam is bent 20mm by a mass 0f 40kg. how much will the beam bend with a mass

Naddik [55]

Answer:

The beam will bend by 50 mm with a mass of 100kg?

Step-by-step explanation:

The first step in solving the problem of direct variation is setting up the relation mathematically.

We can do this as follows:

The bending of the beam varies directly as its mass.

$20 \alpha 40kg$

$\alpha$ here is the symbol representing direct variation. To remove this and replace it with an equality sign, we have to introduce a constant of proportionality, k

$20 = k \times 40$

k = 20 /40 = 0.5

We can now use this to find the distance the beam will bend with a mass of 100kg?

This will be

$Bending = 0.5 \times 100 =50mm$

There fore, the beam will bend by 50 mm with a mass of 100kg?

6 0

4 years ago

Read 2 more answers

The sum of the lengths of two opposite sides of the circumscribed quadrilateral is 10 cm, and its area is 12 cm2. Find the radiu

PtichkaEL [24]

Answer:

1.2 cm

Step-by-step explanation:

The area of sircumscribed quadrilateral over a circle is equal to

$A=s\cdot r,$

where s is semi-perimeter of the quadrilateral and r is the radius of the circle.

Use property of circumscribed quadrilateral: The sums of the opposite sides are equal.

So, if the sum of two opposite sides of the circumscribed quadrilateral is 10 cm, then the sum of another two sides is also 10 cm and the perimeter of the quadrilateral is 20 cm. Hence,

$s=\dfrac{20}{2}=10\ cm$