<h3>
Answer: Approximately 6.58 years old</h3>
The more accurate value is 6.57881347896059, which you can round however you need. I picked two decimal places.
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Explanation:
Let's pick a starting value of the car. It doesn't matter what the starting value, but it might help make the problem easier. Let's say A = 1000. Half of that is 1000/2 = 500.
So we want to find out how long it takes for the car's value to go from $1000 to $500 if it depreciates 10% per year.
The value of r is r = 0.10 as its the decimal form of 10%
t is the unknown number of years we want to solve for
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y = A(1 - r)^t
500 = 1000(1 - 0.1)^t
500 = 1000(0.9)^t
1000(0.9)^t = 500
0.9^t = 500/1000
0.9^t = 0.5
log( 0.9^t ) = log( 0.5 )
t*log( 0.9 ) = log( 0.5 )
t = log( 0.5 )/log( 0.9 )
t = 6.57881347896059
Note the use of logs to help us isolate the exponent.
Answer:
x = 14
Step-by-step explanation:
2x+4 - 12 = 20
2x - 8 = 20
2x = 28
x = 14
Before her promotion, Mitch was receiving $40,000 per year
after tax. Since the loan payment is 4%, therefore the money that goes to the
loan is:
Loan payment = $40,000 * 0.04
Loan payment = $1,600
After her promotion, Mitch is now receiving:
New salary = $40,000
* 1.25
New salary = $50,000
Therefore the new loan payment becomes:
New loan payment = $50,000 * 0.04
New loan payment = $2,000
Therefore Mitch is paying an extra payment of:
$2,000 - $1,600 = $400
Answer: $400
