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salantis [7]
3 years ago
10

Help with this question asap

Mathematics
2 answers:
Softa [21]3 years ago
8 0

Answer:

ruiwghyrvefufcfuerfyurtgreufru

Step-by-step explanation:

Step2247 [10]3 years ago
8 0

Answer:

XY = 8

Step-by-step explanation:

it is congruent to the other triangle, if you look at it from the same angel it says it equals 8, idk if that  makes sense but hope it helps

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Step-by-step explanation:

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If you cut a 3 3/4 ft. length of wire into pieces that 1/4 ft. long, how many pieces of wire will you have?
lukranit [14]

Answer:

I think it would be 15

Step-by-step explanation:

6 0
3 years ago
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What kind of background would fit?
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Is this even math

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6 0
3 years ago
Help me please asap I need to know fully how to solve this problem
vivado [14]
Consider the absolute value, because we only worry about the quadrant later.

\text{Consider: } sin(A) = |-\frac{\sqrt{3}}{4}|
sin(A) = \frac{\sqrt{3}}{4}

Thus, we know that the hypotenuse has a length of 4 units, and the side opposite the angle, A is √3, because this is the nature of the sine function in relation to its triangular component.

The missing side can be found using Pythagoras' Theorem:
4² - (√3)² = x²
16 - 3 = x²
13 = x²
x = √13

\therefore tan(A) = \pm \sqrt{\frac{3}{13}}

Since angle A is in the third quadrant, the tangent function will produce a positive angle.

tan(A) = \sqrt{\frac{3}{13}}
\text{Rationalise the denominator: } \frac{\sqrt{3}}{\sqrt{13}} \cdot \frac{\sqrt{13}}{\sqrt{13}}

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7 0
3 years ago
Triangles P Q R and S T U are shown. Angles P R Q and T S U are right angles. The length of P Q is 20, the length of Q R is 16,
dimaraw [331]

Answer:

\angle P

Step-by-step explanation:

Given

\triangle PRQ = \triangle TSU = 90^o

PQ = 20     QR = 16    PR = 12

ST = 30       TU = 34    SU = 16

<em>See attachment</em>

Required

Which sine of angle is equivalent to \frac{4}{5}

Considering \triangle PQR

We have:

\sin(P) = \frac{QR}{PQ} --- i.e. opposite/hypotenuse

So, we have:

\sin(P) = \frac{16}{20}

Divide by 4

\sin(P) = \frac{4}{5}

Hence:

\angle P is correct

7 0
3 years ago
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