Sorry that's all i know
<h3>that is in my answer</h3>
<h2>#carryonlearning:-D</h2>
Answer: z = -5/-3
Step-by-step explanation:
(3z−11)+(6−6z)
3z - 11 + 6 - 6z
- 6z + 3z - 11 + 6
- 3z - 5
z = -5/-3
Answer:
The velocities after 739 s of firing of each engine would be 6642.81 m/s in the x direction and 5306.02 in the y direction
Step-by-step explanation:
- For a constant acceleration:
, where 
is the final velocity in a direction after the acceleration is applied, 
is the initial velocity in that direction before the acceleration is applied, a is the acceleration applied in such direction, and t is the amount of time during where that acceleration was applied. - <em>Then for the x direction</em> it is known that the initial velocity is
5320 m/s, the acceleration (the applied by the engine) in x direction is 
1.79 m/s2 and, the time during the acceleration was applied (the time during the engines were fired) of the is 739 s. Then: 
- In the same fashion, <em>for the y direction</em>, the initial velocity is
0 m/s, the acceleration in y direction is 
7.18 m/s2, and the time is the same that in the x direction, 739 s, then for the final velocity in the y direction: 
Answer:
you press the paper clip symbol
Step-by-step explanation:
What about if you use the distributive property? You could do 1(x+13) because the 1 would distribute to the x and the 13 making it x+13. Hope that is helpful.
