Answer:
Given: In parallelogram ABCD, AC=BD
To prove : Parallelogram ABCD is rectangle.
Proof : in △ACB and △BDA
AC=BD ∣ Given
AB=BA ∣ Common
BC=AD ∣ Opposite sides of the parallelogram ABCD
△ACB ≅△BDA∣SSS Rule
∴∠ABC=∠BAD...(1) CPCT
Again AD ∥ ∣ Opposite sides of parallelogram ABCD
AD ∥BC and the traversal AB intersects them.
∴∠BAD+∠ABC=180∘ ...(2) _ Sum of consecutive interior angles on the same side of the transversal is
180∘
From (1) and (2) ,
∠BAD=∠ABC=90∘
∴∠A=90∘ and ∠C=90∘
Parallelogram ABCD is a rectangle.
7/16=0.4375
193/1000=0.193
0.4375 is bigger than 0.193 by 0.2445
Answer:
3 calories
Step-by-step explanation: 100%-40%=60% .6*5=3 calories
Answer:
51°
Step-by-step explanation:
Given
<QPR = 39°
<PQR = 90° ( inscribed angle in semi circle)
Now
<QPR + <PQR + <PRQ = 180° { being sum of angles of triangle)
39° + 90° + <PRQ = 180°
<PRQ = 180° - 39° - 90°
<PRQ = 51°
Hope it will help :)
17x11=187 need more character there done
