The volume of such a can with base radius
and height
would be
We desire the base's circumference and the can's height to add to 120, i.e.
Substituting this into
allows us to reduce the volume to a function of a single variable
:
Taking the derivative with respect to
yields
Set this equal to 0 and find any critical points:
This suggests the can will have maximum volume when its radius is
cm, which would give a volume of about 20,371 sq. cm.
Answer:
-7/3
Step-by-step explanation:
When finding slope from a graph, I always look for places where the graph crosses grid intersections. One of these is the y-intercept, (0, 40).
You have to go quite some distance to find another. It looks to me like the next grid crossing is at (30, -30). At this point, you can do either of two things:
- find the ratio of grid squares
- use the slope formula
What you want to calculate is the ratio of the change in vertical height (rise) to the change in horizontal distance (run). If you use grid squares, you need to make sure the grid has the same number of units horizontally as vertically. (Here a grid square is 10 units in each direction, so we're OK on that point.)
We have observed that the line falls 7 grid squares vertically for a change of 3 grid squares to the right. So, the slope using grid squares is ...
m = rise/run = -7/3
Using the slope formula, we calculate the slope to be ...
m = (y2 -y1)/(x2 -x1)
m = (-30 -40)/(30 -0) = -70/30 = -7/3
The slope of the line is -7/3.
Answer:
$151,200
Step-by-step explanation:
According to the problem, calculation of the given data are as follows,
Cost of Equipment = $634,800
Salvage Value = $30,000
Estimated Life = 4 years
So, we can calculate depreciation for first year by using following formula,
Amount of depreciation = Depreciable base amount ÷ Estimated Life
Where, Depreciable base amount = Cost of Equipment - Salvage Value
= $634,800 - $30,000 = $604,800
By putting the value, we get
Amount of depreciation = $604,800 ÷ 4
= $151,200
Here you go i hope this helped you