By direct correspondence AB = PQ
ax^2 + bx+c =0
discriminant b^2-4ac
(-6)^2 - 4(1) *(9)
36-36 = 0
if the discriminant >0 it has 2 real roots
= 0 it has 1 root of multiplicity 2
< 0 has 2 imaginary root
x^2 - 6x + 9 = 0
(x-3)(x-3)=0
root is 3 multiplicity 2
Answer : double root real and rational
Answer:
1. -m(-8n^2-7n+1)
2. (2w+7c) (v+7c)
5. (q+3r)(q^2-3qr+9r^2)
7. x= - 4/7, 1/9
Step-by-step explanation:
The value of (f/g)(-1) is 0, value of (g . f) (2) is -3√3, the value of (g - f)(-1) is √15, and the value of (g + f) (2) is √3 - 3
<h3>What is a function?</h3>
It is defined as a special type of relationship, and they have a predefined domain and range according to the function every value in the domain is related to exactly one value in the range.
We have two functions:
f(x) = 1 - x²
g(x) = √(11 - 4x)
f(-1) = 0
g(-1) = √15
f(2) = -3
g(2) = √3
(f/g)(-1) = f(-1)/g(-1) = 0/√15 = 0
(g . f) (2) = g(2)f(2) = (√3)(-3) = -3√3
(g - f)(-1) = g(-1) - f(-1) = √15 - 0 = √15
(g + f) (2) = g(2) + f(2) = √3 + (-3) = √3 - 3
Thus, the value of (f/g)(-1) is 0, value of (g . f) (2) is -3√3, the value of (g - f)(-1) is √15, and the value of (g + f) (2) is √3 - 3
Learn more about the function here:
brainly.com/question/5245372
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