Answer:
23 chalkboards
Step-by-step explanation:
Given:
Mean length = 5 m
Standard deviation = 0.01
Number of units ordered = 1000
Now,
The z factor =
or
The z factor =
or
Z = - 2
Now, the Probability P( length < 4.98 )
Also, From z table the p-value = 0.0228
therefore,
P( length < 4.98 ) = 0.0228
Hence, out of 1000 chalkboard ordered (0.0228 × 1000) = 23 chalkboard are likely to have lengths of under 4.98 m.
I think you meant to write
(2 × 10⁶) × 0.00009
First, convert 0.00009 to scientific notation:
0.00009 = 9 × 10 ⁻⁵
Then
(2 × 10⁶) × 0.00009 = (2 × 10⁶) × (9 × 10 ⁻⁵)
… = (2 × 9) × (10⁶ × 10 ⁻⁵)
… = 18 × 10¹
… = 1.8 × 10²
Answer:
z = - 20
Step-by-step explanation:
3 - z/4 = 8
-z/4 = 5
z = -20
Answer:
1. Increases
2. Increase ( I think)
3.reflects over y-axis
Step-by-step explanation: