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Viefleur [7K]
3 years ago
15

Please help guys ♡♡♡♡♡♡​

Mathematics
2 answers:
kakasveta [241]3 years ago
7 0

Answer:

hope this helped uh

if u like then u can follow me

Fittoniya [83]3 years ago
7 0

Answer:

MON  = ∠ 154°

Step-by-step explanation:

Please find file attached

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State the collision theory <br>​
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3 years ago
In a study of the effects of acid rain, a random sample of 100 trees from a particular forest is examined. Forty percent of thes
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Step-by-step explanation:

The sample mean is an unbiased estimator of the true (unknown) population mean and The sampling distribution shows how the sample mean will vary among repeated samples. In the case above the samples are selected at random from a normally distributed population, and the number of samples selected (n=100) is a bit large therefore the sampling distribution will be approximately normal.

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3 years ago
Cos square 30 degree minus sin square 30 degree is equals to 1 minus 2 sin square 30 degree​
babunello [35]

Answer:

see explanation

Step-by-step explanation:

Not sure quite what you are asking, but

Using the trigonometric identity

cos² x = 1 - sin²x, then

cos²x - sin²x

= 1 - sin²x - sin²x

= 1 - 2sin²x

Thus

cos²30° - sin²30° = 1 - 2sin²30°

4 0
3 years ago
Write the quadratic function with the following transformations: vertical shrink by 3, left 4, down 9.
xz_007 [3.2K]
\bf \qquad \qquad \qquad \qquad \textit{function transformations}&#10;\\ \quad \\\\&#10;% left side templates&#10;\begin{array}{llll}&#10;f(x)=&{{  A}}({{  B}}x+{{  C}})+{{  D}}&#10;\\ \quad \\&#10;y=&{{  A}}({{  B}}x+{{  C}})+{{  D}}&#10;\\ \quad \\&#10;f(x)=&{{  A}}\sqrt{{{  B}}x+{{  C}}}+{{  D}}&#10;\\ \quad \\&#10;f(x)=&{{  A}}(\mathbb{R})^{{{  B}}x+{{  C}}}+{{  D}}&#10;\\ \quad \\&#10;f(x)=&{{  A}} sin\left({{ B }}x+{{  C}}  \right)+{{  D}}&#10;\end{array}\\\\&#10;--------------------\\\\

\bf \bullet \textit{ stretches or shrinks horizontally by  } {{  A}}\cdot {{  B}}\\\\&#10;\bullet \textit{ flips it upside-down if }{{  A}}\textit{ is negative}&#10;\\\\&#10;\bullet \textit{ horizontal shift by }\frac{{{  C}}}{{{  B}}}\\&#10;\left. \qquad  \right. if\ \frac{{{  C}}}{{{  B}}}\textit{ is negative, to the right}\\\\&#10;\left. \qquad  \right.  if\ \frac{{{  C}}}{{{  B}}}\textit{ is positive, to the left}\\\\

\bf \bullet \textit{ vertical shift by }{{  D}}\\&#10;\left. \qquad  \right. if\ {{  D}}\textit{ is negative, downwards}\\\\&#10;\left. \qquad  \right. if\ {{  D}}\textit{ is positive, upwards}\\\\&#10;\bullet \textit{ period of }\frac{2\pi }{{{  B}}}


with that template in mind, let's see

so, the parent equation could be
y = x²      ====>     y = A(x + C)² + D

shrink by 3, A = 3
left 4, C = +4
down 9, D  = 9
7 0
3 years ago
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