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3 years ago

Please help guys ♡♡♡♡♡♡

Mathematics

2 answers:

kakasveta [241]3 years ago

7 0

Answer:

hope this helped uh

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Fittoniya [83]3 years ago

7 0

Answer:

MON = ∠ 154°

Step-by-step explanation:

Please find file attached

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What are the steps to solve d=1/e + 1/f for e ?

konstantin123 [22]

Solve for e

d = 1/e + 1/f

Move 1/f to the left side of the = sign

d - 1/f = 1/e

Multiply each side by e

e(d - 1/f) = e(1/e)

e(d - 1/f) = 1

Divide out (d - 1/f)

e(d - 1/f) / (d - 1/f) = 1 / (d - 1/f)

e = 1 / (d - 1/f)

8 0

3 years ago

Pls help, will give brainlist if u give me the answer!!

timama [110]

Answer:

$7.5 plus $65 per hour

Step-by-step explanation:

We are trying to find the minimum she can make in one day. The minimum amount of hours she can work is 1, so find y when x=1:

y=7.5x+65

y=7.5(1)+65

y=7.5+65

6 0

3 years ago

I need the answer and the work (it’s geometry)

Kisachek [45]

Answer:

Step-by-step explanation:

The starting point is B and the ray extends towards A.

So the asnwer is D.

6 0

3 years ago

I was to lazy to do this earlier and i have no time HELP

Svetllana [295]

Download the app photomath it shows you step by step :)

8 0

2 years ago

In a particular game, a fair die is tossed. If the number of spots showing is either four or five, you win $1. If the number of

TiliK225 [7]

Answer:

The probability that you win at least $1 both times is 0.25 = 25%.

Step-by-step explanation:

For each game, there are only two possible outcomes. Either you win at least $1, or you do not. Games are independent. This means that the binomial probability distribution is used to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

In which $C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And p is the probability of X happening.

Probability of winning at least $1 on a single game:

The die has 6 sides.

If it lands on 4, 5 or 6(either of the three sides), you win at least $1. So

$p = \frac{1}{2} = 0.5$

You are going to play the game twice.

This means that $n = 2$

The probability that you win at least $1 both times is

This is P(X = 2).

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 2) = C_{2,2}.(0.5)^{2}.(0.5)^{2} = 0.25$

The probability that you win at least $1 both times is 0.25 = 25%.

4 0

2 years ago

Please help guys ♡♡♡♡♡♡​

Please help guys ♡♡♡♡♡♡