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2 years ago

Y + y PLS HELP pls pls pls

Mathematics

2 answers:

erastovalidia [21]2 years ago

7 0

Answer:

y=0

Step-by-step explanation:

Simplifying

y + y = 0

Combine like terms: y + y = 2y

2y = 0

Solving

2y = 0

Solving for variable 'y'.

Move all terms containing y to the left, all other terms to the right.

Divide each side by '2'.

y = 0

Simplifying

y = 0

Kruka [31]2 years ago

7 0

Answer:

The correct answer is,

$2y$

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Evaluate n+2x2 when n=3 and x=−2.

krok68 [10]

Answer:

When n=3 and x=−2 the answer is 11.

Step-by-step explanation:

Given:

Let p (n,x) be the function such that

$p (n,x) = n + 2x^{2}$

To Find:

p (n,x) = p ( 3, -2) = ?

Solution:

$p (n,x) = n + 2x^{2}$

Substituting n = 3 and x = -2 we get

$p (3, -2) = 3 + 2(-2)^{2}$

Negative square gives positive number therefore (-2)²=4

$p (3, -2) = 3 + 2\times 4$

$p (3, -2) = 3 + 8\\p (3, -2) = 11$

When n=3 and x=−2 the answer is 11.

7 0

3 years ago

Show that area under multivariate normal distribution over the whole range in unity. Find characteristics function of multivaria

kenny6666 [7]

Answer:

here is the answer

Step-by-step explanation:

you may please search it

8 0

3 years ago

Solving Exponential Equations (lacking a common base)<br> 31^d=38

Bond [772]

Answer:

d = log 38/log31

d = 1.06

Step-by-step explanation:

31 ^ d = 38

Take log of both sides since the exponential equation have different base (always)

d log 31 = log 38

d = log 38 / log 31

d = 1.58 / 1.491

d = 1.06.

We can actually check to see if this is correct.

Substituting d = 1.06

31^ 1.06 = 38.092

(You see, that's approximately correct)

Keep learning, maths is fun!

8 0

3 years ago

Show working please

shutvik [7]

Answer:

Step-by-step explanation:

1.159 R (remainder) 42

| ------------------------

73 | 84.649

-73

116 (brought 6 down)

-73

434 (brought 4 down)

-365

699 (brought 9 down)

-657

42 is the remainder

6 0

3 years ago

Read 2 more answers

Express the integral as a limit of Riemann sums. Do not evaluate the limit. (Use the right endpoints of each subinterval as your

Veronika [31]

The expression of integral as a limit of Riemann sums of given integral $\int\limits^5_b {1} \, x/(2+x^{3}) dx$ is 4 $\lim_{n \to \infty}$ ∑ $n(n+4i)/2n^{3}+(n+4i)^{3}$ from i=1 to i=n.

Given an integral $\int\limits^5_b {1} \, x/(2+x^{3}) dx$ .

We are required to express the integral as a limit of Riemann sums.

An integral basically assigns numbers to functions in a way that describes displacement, area, volume, and other concepts that arise by combining infinite data.

A Riemann sum is basically a certain kind of approximation of an integral by a finite sum.

Using Riemann sums, we have :

$\int\limits^b_a {f(x)} \, dx$ = $\lim_{n \to \infty}$ ∑f(a+iΔx)Δx ,here Δx=(b-a)/n

$\int\limits^5_1 {x/(2+x^{3}) } \, dx$ =f(x)= $x/2+x^{3}$

⇒Δx=(5-1)/n=4/n

f(a+iΔx)=f(1+4i/n)

f(1+4i/n)= $[n^{2}(n+4i)]/2n^{3}+(n+4i)^{3}$

$\lim_{n \to \infty}$ ∑f(a+iΔx)Δx=

$\lim_{n \to \infty}$ ∑ $n^{2}(n+4i)/2n^{3}+(n+4i)^{3}4/n$

=4 $\lim_{n \to \infty}$ ∑ $n(n+4i)/2n^{3}+(n+4i)^{3}$

Hence the expression of integral as a limit of Riemann sums of given integral $\int\limits^5_b {1} \, x/(2+x^{3}) dx$ is 4 $\lim_{n \to \infty}$ ∑ $n(n+4i)/2n^{3}+(n+4i)^{3}$ from i=1 to i=n.

Learn more about integral at brainly.com/question/27419605

#SPJ4

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2 years ago