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Anni [7]
2 years ago
5

A computer store decides to increase the prices of all the items it sells by 15%. the store manager uses matrices to prepare the

new price list. matrix a contains the unit price of each product in each category. matrix b contains the revised price of each item in each category. how can the manager obtain the entries for matrix b? a. by adding 15 to each entry of matrix a b. by multiplying each entry of matrix a by 15 c. by multiplying each entry of matrix a by 1.15 d. by multiplying each entry of matrix a by 0.15
Mathematics
1 answer:
Andrews [41]2 years ago
7 0

The matrix exists as a set of numbers placed in rows and columns to create a rectangular array. The manager could achieve scalar multiplication on Matrix A, utilizing the scalar 1.15.

<h3>What is the matrix?</h3>

The matrix exists as a set of numbers placed in rows and columns to create a rectangular array. The numbers exist named the elements, or entries, of the matrix. Matrices contain wide applications in engineering, physics, economics, and statistics as well as in different branches of mathematics.

Increasing the price by 15% would mean we exist taking 100% of the value + another 15%

100 + 15 = 115%

115% = 115/100 = 1.15.

Multiplying every value in Matrix A by 1.15 will give the price raised by 15%.

Therefore, the correct answer is option c. by multiplying each entry of matrix a by 1.15.

To learn more about matrix refer to:

brainly.com/question/12567347

#SPJ4

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What is the y-intercept of this quadratic function f(I)=-i2+10i-22
const2013 [10]

The y-intercept of the quadratic equation is -47.

<h3>What is Quadratic Equation?</h3>

A quadratic equation is an algebraic equation of the second degree in x. The quadratic equation in its standard form is ax² + bx + c = 0, where a and b are the coefficients, x is the variable, and c is the constant term.

Here, given quadratic equation;

    f(i) = i² + 10i - 22

or, y = i² + 10i - 22

     y = i² + 2.5x - (47-25)    

    y = i² + 2.5x + 25 - 47

    y = (i+5)² - 47

Thus, the y-intercept of the quadratic equation is -47.

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4 0
2 years ago
In triangle ABC, what is the measure of angle C if A = 85°, a = 35, and c = 25?
yan [13]
Do you have a formula sheet or was one provided to you
5 0
3 years ago
Read 2 more answers
Can you help me please?
iren [92.7K]

Finding the volume of a cube involves multiplying with this formula.

Height * Width * Length = volume

To find what the side lengths are, we can take the cube root of 64.

∛64 = 4

Height = 4

Width = 4

Length = 4

These sides are multiplied together to get 64.

The only answer choice that makes sense is Option A.

______

Best Regards,

Wolfyy :)

6 0
3 years ago
Read 2 more answers
How many terms of the arithmetic sequence {1,22,43,64,85,…} will give a sum of 2332? Show all steps including the formulas used
MA_775_DIABLO [31]

There's a slight problem with your question, but we'll get to that...

Consecutive terms of the sequence are separated by a fixed difference of 21 (22 = 1 + 21, 43 = 22 + 21, 64 = 43 + 21, and so on), so the <em>n</em>-th term of the sequence, <em>a</em> (<em>n</em>), is given recursively by

• <em>a</em> (1) = 1

• <em>a</em> (<em>n</em>) = <em>a</em> (<em>n</em> - 1) + 21 … … … for <em>n</em> > 1

We can find the explicit rule for the sequence by iterative substitution:

<em>a</em> (2) = <em>a</em> (1) + 21

<em>a</em> (3) = <em>a</em> (2) + 21 = (<em>a</em> (1) + 21) + 21 = <em>a</em> (1) + 2×21

<em>a</em> (4) = <em>a</em> (3) + 21 = (<em>a</em> (1) + 2×21) + 21 = <em>a</em> (1) + 3×21

and so on, with the general pattern

<em>a</em> (<em>n</em>) = <em>a</em> (1) + 21 (<em>n</em> - 1) = 21<em>n</em> - 20

Now, we're told that the sum of some number <em>N</em> of terms in this sequence is 2332. In other words, the <em>N</em>-th partial sum of the sequence is

<em>a</em> (1) + <em>a</em> (2) + <em>a</em> (3) + … + <em>a</em> (<em>N</em> - 1) + <em>a</em> (<em>N</em>) = 2332

or more compactly,

\displaystyle\sum_{n=1}^N a(n) = 2332

It's important to note that <em>N</em> must be some positive integer.

Replace <em>a</em> (<em>n</em>) by the explicit rule:

\displaystyle\sum_{n=1}^N (21n-20) = 2332

Expand the sum on the left as

\displaystyle 21 \sum_{n=1}^N n-20\sum_{n=1}^N1 = 2332

and recall the formulas,

\displaystyle\sum_{k=1}^n1=\underbrace{1+1+\cdots+1}_{n\text{ times}}=n

\displaystyle\sum_{k=1}^nk=1+2+3+\cdots+n=\frac{n(n+1)}2

So the sum of the first <em>N</em> terms of <em>a</em> (<em>n</em>) is such that

21 × <em>N</em> (<em>N</em> + 1)/2 - 20<em>N</em> = 2332

Solve for <em>N</em> :

21 (<em>N</em> ² + <em>N</em>) - 40<em>N</em> = 4664

21 <em>N</em> ² - 19 <em>N</em> - 4664 = 0

Now for the problem I mentioned at the start: this polynomial has no rational roots, and instead

<em>N</em> = (19 ± √392,137)/42 ≈ -14.45 or 15.36

so there is no positive integer <em>N</em> for which the first <em>N</em> terms of the sum add up to 2332.

4 0
2 years ago
Good at math &amp; need points? help!!
Greeley [361]

Answer:

5

Step-by-step explanation:

5 0
3 years ago
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