Answer:
Number of hours= 48 hours
Step-by-step explanation:
Giving the following information:
Hourly rate= $7.25
Total earned= $348
<u>To calculate the number of hours worked, we need to use the following formula:</u>
Total earned= hourly rate*number of hours
number of hours= total earned / hourly rate
number of hours= 348 / 7.25
number of hours= 48 hours
Answer:
Option D is correct.
13x = 39
Step-by-step explanation:
The system of equation is given:
....[1]
.....[2]
Multiply equation [1] by 5 to both sides we have;
.....[3]
Using elimination method:
Add [2] and [3] equations to eliminate y and solve for x, we have;
Divide both sides by 13 we get;
x = 3
Substitute x in [1] we have;
2(3)-y = -4
6-y = -4
Subtract 6 from both sides we have;
-y = -10
Divide both sides by -1 we have;
y = 10
⇒Solution: (3, 10)
Therefore, an equation can replace 3x+5y = 59 in the original system and still produce the same solution is,
13x = 39
We can solve by figuring the area of the rectangle then add it to the area of the semicircle.
Area of the rectangle: length · width = 6 · 10 = 60 ft²
Area of the semicircle: (πd²)/8 = (3.14 · 6²)/8 = (3.14 · 36)/8 = 14.13 ft²
Total area of the figure: 60 + 14.13 = 74.13 ft² ≈ 74 ft²
Answer:
-0.00572
Step-by-step explanation:
0.572 143/250 57.2%
then divide:)
Answer:
34.87% probability that all 5 have a wireless device
Step-by-step explanation:
For each student, there are only two possible outcomes. Either they own a wireless device, or they do not. The probability of a student owning a wireless device is independent from other students. So we use the binomial probability distribution to solve this question.
Binomial probability distribution
The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.
In which is the number of different combinations of x objects from a set of n elements, given by the following formula.
And p is the probability of X happening.
81% of students own a wireless device.
This means that
If 5 students are selected at random, what is the probability that all 5 have a wireless device?
This is P(X = 5) when n = 5. So
34.87% probability that all 5 have a wireless device