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Afina-wow [57]
2 years ago
11

Jimmy’s family moved to a tropical climate. For the year that followed, he recorded the number of days that had a temperature ab

ove 40 degrees C each month. His data contained -
14, 14, 10, 12, 11, 13, 11, 11, 14, 10, 13 and 8

1) Find the mean for his data set of days that had a temperature above 40 degrees C.

2) Find the median for his data set of days that had a temperature above 40 degrees C.

3) Find the mode for his data set of days that had a temperature above 40 degrees C.

4) If, instead, there are 5 more days per month that had a temperature above 40 degrees C, what will be the mean for the data?

5) If, instead, there are 2 more days per month that had a temperature above 40 degrees C, what will be the mode for the data?

6) If the number of days per month that had a temperature above 40 degrees C, doubles each month in that year, what will be the median for the data?

7) For what value of x will 9, 16, and x have the same mean (average) as that of 26 and 12?

8) For what value of x will 55 and x have the mean (average) as 67?

9) The mean (average) weight of three boys is 40 pounds. One of the boys weighs 50 pounds. The other two boys have the same weight. Find the weight of each of the boys?

10) A cat consumes 2 cups of milk every day. How much milk does that cat drink on an average in a week?

11) What is the mode for the above question?
Mathematics
2 answers:
AveGali [126]2 years ago
8 0

Answer:

.

Step-by-step explanation:

JulsSmile [24]2 years ago
4 0
The answer would be 4 as it more than 40 degrees whoch will allow to it record
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inna [77]

Answer:

a = 85° , b = 30° , c = 65°

Step-by-step explanation:

∠ a and 85° are alternate angles and are congruent , so

a = 85°

∠ c and 65° are alternate angles and are congruent , so

c = 65°

a, b and c lie on a straight line and sum to 180° , that is

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8 0
2 years ago
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bagirrra123 [75]
If you put brackets around (2+1), your method of working is: 
1) 15-4*(2+1)=3 
2) 15-4*3=3
3) 15-12=3
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3 0
3 years ago
Find the absolute maximum value for the function f(x) = x^2 − 4, on the interval [–3, 0) U (0, 2].
Andreyy89

Answer:

5

Step-by-step explanation:

The function y=x^2 -4 is

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  • is increasing for all x\in (0,2]

(see attached diagram for details).

The maximum value of the function is at endpoints -3 or 2. find y(-3) and y(2):

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So, the maximum value is 5.

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