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kkurt [141]
3 years ago
11

A rocket is fired straight up with an initial velocity of 256 ft/s. The rocket is fired from a platform that is 576 feet above t

he ground. Use 16 for g. 1.) Write a function, s(t), that models the height of the rocket at time t seconds. This rocket reaches a maximum height of 1600 ft; use this fact to validate your model.
Mathematics
1 answer:
zheka24 [161]3 years ago
7 0

Answer:

b kjbkj kj n jkhnji kjjjuhjkjhhj

Step-by-step explanation:

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Domain and range of the function f(x)= 7x^5<br> PLEASE HELP I LITERALLY CANT DO IT
sineoko [7]

Answer:

Domain: all real numbers

Range: all real numbers

Step-by-step explanation:

The domain is all x values, and the range is all y values.

<u><em>Domain:</em></u>

The domain is all real numbers except where the slope is undefined (a vertical line). In this case, no number makes the expression undefined, so the domain is:

all real numbers

<u><em>Interval notation:</em></u><em>  </em>(-∞,∞)

all negative numbers and positive numbers (all real numbers)

<em><u>Set-Builder Notation:</u></em> {x | x ∈ R }

<em><u>Range:</u></em>

The range is the set of all valid values. Graph the line and check. Since all values of y are valid, the range is:

all real numbers

<u><em>Interval notation:</em></u><em>  </em>(-∞,∞)

all negative numbers and positive numbers (all real numbers)

<em><u>Set-Builder Notation:</u></em> {x | x ∈ R }

:Done

3 0
2 years ago
The length of the base edge of a pyramid with a regular hexagon base is represented as x. The height of the pyramid is 3 times l
sergij07 [2.7K]

Answer:

(a)

h=3x

(b)

A=\frac{\sqrt{3} }{4} x^2

(c)

A=\frac{3\sqrt{3} }{2} x^2

(d)

V=\frac{3\sqrt{3} }{2} x^3 units^3

Step-by-step explanation:

We are given a regular hexagon pyramid

Since, it is regular hexagon

so, value of edge of all sides must be same

The length of the base edge of a pyramid with a regular hexagon base is represented as x

so, edge of base =x

b=x

Let's assume each blank spaces as a , b , c, d

we will find value for each spaces

(a)

The height of the pyramid is 3 times longer than the base edge

so, height =3*edge of base

height=3x

h=3x

(b)

Since, it is in units^2

so, it is given to find area

we know that

area of equilateral triangle is

=\frac{\sqrt{3} }{4} b^2

h=3x

b=x

now, we can plug values

A=\frac{\sqrt{3} }{4} x^2

(c)

we know that

there are six such triangles in the base of hexagon

So,

Area of base of hexagon = 6* (area of triangle)

Area of base of hexagon is

=6\times \frac{\sqrt{3} }{4} x^2

=\frac{3\sqrt{3} }{2} x^2

(d)

Volume=(1/3)* (Area of hexagon)*(height of pyramid)

now, we can plug values

Volume is

=\frac{1}{3}\times\frac{3\sqrt{3} }{2} x^2\times (3x)

V=\frac{3\sqrt{3} }{2} x^3 units^3


3 0
3 years ago
Read 2 more answers
What is the apparent solution to the system of equations?
Alexus [3.1K]
X = 3
y = -3

You will see this using any graphing tool at your disposal. 
7 0
3 years ago
When comparing the graphs of y = x and y &gt; x, what is a difference in the graphs?
mars1129 [50]
I donnt think that there is a solution, but could be wrong
8 0
3 years ago
Find h(k+6) if h(x)=15x+6
goblinko [34]

Answer:

h(k+6) if h(x)=15x+6

h(k+6)=15(k+6)+6=15k+90+6=15k+96

4 0
3 years ago
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