As hamster wheel is circular so for revolution we will find the circumference.
Diameter of the Hamster wheel = 8.5 in
One revolution of the wheel = circumference of the wheel
Circumference = π × d
π = 3.14 and d = 8.5
So, Circumference = 3.14 × 8.5
Circumference = 26.69 in
So in one revolution the hamster wheel travels a distance of 26.69 in
P=44+66+88/2=198/2=99
With Heron formula:
S=root 99*(99-44)(99-66)(99-88)=root 99*55*33*11=root 1976535= 1405.8929.....=1405.9
Answer:
i think its A but im not sure
Answer:
the horizontal position for the left edge of the image is -4.46 cm.
Step-by-step explanation:
The horizontal midpoint of the page is:
21.59 / 2 = 10.79 cm
The horizontal midpoint of the image is given as:
30.51 / 2 = 15.25 cm
These midpoints must be on the same point in the axis.
By taking the leftmost edge of the paper to be point zero on the axis, then, the distance accommodated by the paper is 10.795 cm.
The distance that goes beyond this leftmost edge is computed as;
This is on the negative side on the axis.
Thus the horizontal position for the left edge of the image is -4.46 cm.
2/5 of 50 is 20. 50-20=30. Making FG=30
