Starting on the far right, ones, tens, hundreds, thousands, ten thousands, hundred thousands and millions.
Answer:
P(z>1.3) = 0.9032
Step-by-step explanation:
We are given:
Mean = 5000
Standard deviation = 1000
x = 6300
P(x>6300)=?
z-score =?
z-score = x- mean/standard deviation
z-score = 6300 - 5000/1000
z- score = 1300/1000
z-score = 1.3
So, P(x>6300) = P(z>1.3)
Looking at the z-probability distribution table and finding value:
P(z>1.3) = 0.9032
So, P(z>1.3) = 0.9032
To isolate the variable q, divide both sides by 3:
q3 ÷ 3 = 64 ÷ 3
q = 21.33 or 21 1/3
If the q is cubed(I can't really tell), however, you would use the cube root:
³√q³ = ³√64
q = 4
Answer:
hmmm cant tell if this is a serious question Lol considering you seem pretty smart but if so answer is 23
Step-by-step explanation:
