Answer:3/35
Step-by-step explanation:
Answer:
Answer in terms of a trigonometric function :
Answer in figures

Step-by-step explanation:
Consider the sketch attached below to better understand the problem.
Let x be the distance between point B and the base of the water tower.


From equation 2,
substituting the value of x into equation 1, we get


cross multiplying,



The height of the tower is
in terms of the trig function "Tan"
The equation can simply be evaluated to get the answer in figures since the angles are given in the question
Capacity is the maximum amount that something can contain. Fluid ounces is how much something contains in ounces.
For you to make an equation a quadratic equation, you need everything to be on one side, so you add one to both sides.
<span>2x^2 + 3x + 0=0 </span>
<span>a=2, b=3, c=0 </span>
<span>b^2-4ac (In the next step just plug in your variables) </span>
<span>3^2 - 4(2)(0) </span>
<span>9 - 8(0) </span>
<span>9 - 0 </span>
<span>Your answer=9</span>